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组织。冬眠QueryException:无法解析属性:abc的查询。def。我的包裹。orm。受雇者

  •  1
  • Dan  · 技术社区  · 8 年前

    当我试图执行 insertEmployeeDetails 方法:

    组织。冬眠QueryException:无法解析属性:abc的查询。def。我的包裹。orm。员工[插入员工(名称、定义,(从公司数据中选择value\u emp\u id,其中testing\u id=1234,COMPANY\u Employee\u id=3345))]

    看看类似的关于堆栈溢出的其他帖子,例如,下面的帖子说:

    org.hibernate.QueryException: could not resolve property:

    那个“ 我们不引用数据库列名,而是引用属性名 name definition 如实体类中所定义 Employee 在下面我试图获取列值的子查询 COLUMN_ID SELECT 应该拉动的子查询 value_emp_id 从…起 COMPANY_DATA 表是我提到的一个SQL查询。这需要修改吗?这可能是这种错误的原因吗?请告知。

    Employee.java 具体如下:

    package abc.def.mypackage.orm
    
    @Entity
    @Table(name = "EMPLOYEE")
    public class Employee {
     public int getEmployeeId() {
      return employeeId;
     }
    
     public void setEmployeeId(int employeeId) {
      this.employeeId = employeeId;
     }
    
     public String getName() {
      return name;
     }
    
     public void setName(String name) {
      this.name = name;
     }
    
     public int getIsCorrect() {
      return isCorrect;
     }
    
     public void setIsCorrect(int isCorrect) {
      this.isCorrect = isCorrect;
     }
    
     public int getIsWrong() {
      return isWrong;
     }
    
     public void setIsWrong(int isWrong) {
      this.isWrong = isWrong;
     }
    
     public int getCompanyId() {
      return companyId;
     }
    
     public void setCompanyId(int companyId) {
      this.companyId = companyId;
     }
    
     public Integer getTransactionId() {
      return transactionId;
     }
    
     public void setTransactionId(Integer transactionId) {
     this.transactionId = transactionId;
     }
    
     public String getDefinition() {
      return definition;
     }
    
     public void setDefinition(String definition) {
      this.definition = definition;
     }
    
     @Id
     @Column(name = "EMPLOYEE_ID")
     @GeneratedValue(strategy = GenerationType.AUTO, generator = "seqgen")
     @SequenceGenerator(name = "seqgen", sequenceName = "EMPLOYEE_AUTOINC_SEQ")
     private int employeeId;
    
     @Column(name = "NAME")
     private String name;
    
     @Column(name = "DEFINITION")
     private String definition;
    
     @Column(name = "IS_CORRECT")
     private int isCorrect;
    
     @Column(name = "IS_WRONG")
     private int isWrong;
    
     @Column(name = "COMPANY_ID")
     private int companyId;
    
     @Column(name = "TRANSACTION_ID", nullable = true)
     private Integer transactionId;
    
    
    }
    

    以下是我在方法中使用HQL的方式:

    public boolean insertEmployeeDetails(Employee employee)
        {
            logger.debug("Starting EmployeeDaoImpl.insert()  .....");
            Session session = null;
            Transaction tx = null;
            boolean status = true;
            try {
                session = sessionFactory.openSession();
                tx = session.beginTransaction();
                String hqlInsert = "INSERT INTO Employee (name,definition,"
                        + "( SELECT value_emp_id FROM COMPANY_DATA WHERE testing_id = 1234 AND"
                        + " company_employee_id = 3345))";
    
                int createdEntities = session.createQuery( hqlInsert )
                        .executeUpdate();
    
                session.persist(employee);
                tx.commit();
                System.out.println("Checking for hqlInsert");
                System.out.println(hqlInsert);
    
                System.out.println("Checking for CreatedEntities");
                System.out.println(createdEntities);
            } catch(Exception ex) {
                tx.rollback();
                ex.printStackTrace();
                status = false;
            } finally {
                session.close();
            }
            logger.debug("Completed EmployeeDaoImpl.insert()  .....");
            return status;
        }
    
    1 回复  |  直到 8 年前
        1
  •  1
  •   cнŝdk    8 年前

    这里的问题是你很困惑 createQuery() 具有 createSQLQuery() 因为 createQuery() 执行 HQL SQL

    创建查询

    对于给定的HQL查询字符串 .

    事实上 hqlInsert string 你通过了 createQuery() 方法是 SQL 插入查询,不受支持 ,您需要使用 createSQLQuery() Hibernate