Typescript:如何通过函数参数的值获取提取的联合类型的属性

我想知道是否有一种方法可以让ts编译器确定中的回调类型 useListenAPI 作为

• (data: number[]) => void 如果事件类型===APIType。API1
• (data: {isAdmin: boolean, data: number[]}) => void 如果事件类型===APIType。API2

const enum APIType {
    API1 = 1,
    API2 = 2
}

interface API1{
    type: APIType.API1,
    Data: number[]
}

interface API2{
    type: APIType.API2,
    Data: {
        isAdmin: boolean,
        data: number[]
    }
}

type UnionAPI = API1 | API2;

//ts error
//'eventType' refers to a value, but is being used as a type here. Did you mean 'typeof eventType'?
const useListenAPI = (eventType: APIType, callback: (data:Extract<UnionAPI,{type: eventType}>["Data"]) => void)) => {
    // do whatever
}

//'type: typeof eventType' will make callback is (data: number[]|{isAdmin: boolean, data: number[]}) => void
const useListenAPI = (eventType: APIType, callback: (data:Extract<UnionAPI,{type: typeof eventType}>["Data"]) => void)) => {
    // do whatever
}

我知道使用泛型可以解决这个问题,如下所示,但我只是想知道是否有更简单的版本,或者它是ts编译器无法实现的,因为它是一个运行时的东西

const useListenAPI = <T,>(eventType: APIType, callback: (data:Extract<UnionAPI,{type: T}>["Data"]) => void)) => {
    // do whatever
}

useListenAPI<APIType.API1>(APIType.API1, (data) => {
    // data: number[]
})