跟踪字符串中删除的字符数,python`strip()`

我会分两步来做:首先,去掉前面的,然后去掉后面的。然后您可以计算每侧剥离了多少个字符,并使用字符串切片。你可以用 lstrip() 和 rstrip()

var1 = 'AnAppleADayKeepsTheDoctorAway'
var2 = '000Ig00000noranceIsBliss00000'

num_leading = len(var2) - len(var2.lstrip('0'))
num_trailing = len(var2) - len(var2.rstrip('0'))

print(var2.strip())
print(var1[num_leading:-1*num_trailing])

var1 = 'AnAppleADayKeepsTheDoctorAway'
var2 = '000Ig00000noranceIsBliss00000'
old_length = len(var2)
var2 = var2.strip('0')
diff_length = old_length - len(var2)
var1 = var1[diff_length:len(var1)-diff_length]

你可以用 lstrip(..) 和 rstrip(..) 分别计算每次删除的字符数,并用这些字符进行切片:

var1 = 'AnAppleADayKeepsTheDoctorAway'
var2 = '000Ig00000noranceIsBliss00000'

n0 = len(var2)
var3 = var2.lstrip('0')
nl = n0 - len(var3)

var2s = var3.rstrip('0')

var1s = var1[nl:len(var2s)+nl]

var1s nl lstrip(…) var2s ( var2 两者之后 lstrip(…) rstrip(…) ).

因此,我们得出:

>>> var1s
'ppleADayKeepsTheDocto'
>>> var2s
'Ig00000noranceIsBliss' 

可以使用剥离任一侧后长度的更改来创建索引切片

left = var2.lstrip('0')
start = len(var2) - len(left)

right = var2.rstrip('0')
end = (len(var2) - len(right))

var1 = var1[start: len(var1) - end]
var2 = var2.strip('0')

ppleADayKeepsTheDocto 
Ig00000noranceIsBliss