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将JSON数据流从文本文件加载到对象C中#

poco serialization json c#

1

Caveatrob · 技术社区 · 15 年前

我在用 Newtonsoft.Json.Linq 我想将数据加载到我定义的对象(或结构)中,并将这些对象放入列表或集合中。

目前,我正在提取带有名称索引的JSON属性。

filename = openFileDialog1.FileName;

StreamReader re = File.OpenText(filename);
JsonTextReader reader = new JsonTextReader(re);
string ct = "";

JArray root = JArray.Load(reader);
foreach (JObject o in root)
{
    ct += "\r\nHACCstudentBlogs.Add(\"" + (string)o["fullName"] + "\",\"\");";
}
namesText.Text = ct;

对象定义如下,有时JSON不包含属性值:

class blogEntry
{
    public string ID { get; set; }
    public string ContributorName { get; set; }
    public string Title { get; set; }
    public string Description { get; set; }
    public string CreatedDate { get; set; }
}

2 回复 | 直到 15 年前

1

3

Michael Shimmins 15 年前

你可以使用 JsonConvert.DeserializeObject<T> :

[TestMethod]
public void CanDeserializeComplicatedObject()
{
    var entry = new BlogEntry
    {
        ID = "0001",
        ContributorName = "Joe",
        CreatedDate = System.DateTime.UtcNow.ToString(),
        Title = "Stackoverflow test",
        Description = "A test blog post"
    };

    string json = JsonConvert.SerializeObject(entry);

    var outObject = JsonConvert.DeserializeObject<BlogEntry>(json);

    Assert.AreEqual(entry.ID, outObject.ID);
    Assert.AreEqual(entry.ContributorName, outObject.ContributorName);
    Assert.AreEqual(entry.CreatedDate, outObject.CreatedDate);
    Assert.AreEqual(entry.Title, outObject.Title);
    Assert.AreEqual(entry.Description, outObject.Description);
}

2

11

Nathan Baulch 15 年前

您可以使用 JsonSerializer 班级。

var serializer = new JsonSerializer();
using (var re = File.OpenText(filename))
using (var reader = new JsonTextReader(re))
{
    var entries = serializer.Deserialize<blogEntry[]>(reader);
}