你得不到预期的输出
a handful of threads would have output at once
因为你没有开始
a handful of threads
. 一次只能创建一个线程来执行单个任务,这是
get_instance()
功能。
您可以使用以下代码获得接近所需输出的内容:
import datetime as dt
from concurrent.futures import ThreadPoolExecutor
import os
import threading
import time
def handle_instance(h):
t = dt.datetime.time(dt.datetime.now())
print('[{}] Got instance {}'.format(t, h))
print('[{}] Result is {}'.format(t, h.result()))
print(id(t))
def task():
print("Executing our Task on Process: {}".format(os.getpid()))
time.sleep(3)
return 1
def main():
with ThreadPoolExecutor(3) as th_exec:
for dummy in range(3):
th_future = th_exec.submit(task)
th_future.add_done_callback(handle_instance)
if __name__ == "__main__":
try:
while True:
print('A new cycle of execution just started...')
threading.Thread(target=main, daemon=True).start()
time.sleep(5)
except KeyboardInterrupt:
raise SystemExit('\nexit by user')
输出:
A new cycle of execution just started...
Executing our Task on Process: 2528
Executing our Task on Process: 2528
Executing our Task on Process: 2528
[10:40:19.100711] Got instance <Future at 0x262342a9320 state=finished returned int>
[10:40:19.100711] Got instance <Future at 0x2623425e128 state=finished returned int>
[10:40:19.100711] Result is 1
[10:40:19.100711] Result is 1
[10:40:19.100711] Got instance <Future at 0x26233fe3ef0 state=finished returned int>
[10:40:19.100711] Result is 1
exit by user