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将2dpojo数组序列化为json,在java中,在android上

gson json android java

smatthewenglish · 技术社区 · 7 年前

我正在做一个象棋游戏,我想序列化棋盘,并在每次移动后发送到服务器。我将使用JSON来完成这个任务。

我的游戏被表示为我创建的自定义POJO的二维数组 Piece .

目前我正在创建一个JSON-ISH字符串,而不是实际的JSON,这是个问题,因为现在我不能像真正的JSON那样对待它,索引它,等等。

下面是我用来创建这个JSON-ish构造的代码:

StringBuilder result = new StringBuilder();
for (int i = 0; i < piecesMatrix.length; i++) {
    result.append("\"row " + i + "\":\n");
    for (int j = 0; j < piecesMatrix[i].length; j ++) {
        result.append("\"column " + j + "\": ");
        if (piecesMatrix[i][j] == null || piecesMatrix[i][j] instanceof LegalMove) {
            result.append(" \"null\",\n");
        } else {
            result.append(" \"" + piecesMatrix[i][j].getClass().getSimpleName() + "\",\n");
        }
    }
}
message = result.toString();

结果呈现如下:

[ 10-06 20:35:19.971  7509: 7509 D/Data = 

 ]
"row 0":
"column 0":  "BlackRook",
"column 1":  "BlackKnight",
"column 2":  "BlackBishop",
"column 3":  "BlackQueen",
"column 4":  "BlackKing",
"column 5":  "BlackBishop",
"column 6":  "BlackKnight",
"column 7":  "BlackRook",
"row 1":
"column 0":  "BlackPawn",
"column 1":  "BlackPawn",
"column 2":  "BlackPawn",
"column 3":  "BlackPawn",
"column 4":  "BlackPawn",
"column 5":  "BlackPawn",
"column 6":  "BlackPawn",
"column 7":  "BlackPawn",
"row 2":
"column 0":  "null",
"column 1":  "null",
"column 2":  "null",
"column 3":  "null",
"column 4":  "null",
"column 5":  "null",
"column 6":  "null",
"column 7":  "null",
"row 3":
"column 0":  "null",
"column 1":  "null",
"column 2":  "null",
"column 3":  "null",
"column 4":  "null",
"column 5":  "null",
"column 6":  "null",
"column 7":  "null",
"row 4":
"column 0":  "null",
"column 1":  "WhitePawn",
"column 2":  "null",
"column 3":  "null",
"column 4":  "null",
"column 5":  "null",
"column 6":  "null",
"column 7":  "null",
"row 5":
"column 0":  "null",
"column 1":  "null",
"column 2":  "null",
"column 3":  "null",
"column 4":  "null",
"column 5":  "null",
"column 6":  "null",
"column 7":  "null",
"row 6":
"column 0":  "WhitePawn",
"column 1":  "null",
"column 2":  "WhitePawn",
"column 3":  "WhitePawn",
"column 4":  "WhitePawn",
"column 5":  "WhitePawn",
"column 6":  "WhitePawn",
"column 7":  "WhitePawn",
"row 7":
"column 0":  "WhiteRook",
"column 1":  "WhiteKnight",
"column 2":  "WhiteBishop",
"column 3":  "WhiteQueen",
"column 4":  "WhiteKing",
"column 5":  "WhiteBishop",
"column 6":  "WhiteKnight",
"column 7":  "WhiteRook",

问题是,我如何将其转换为真正的JSON?

理想情况下,我希望输出如下:

"row 0":
    "column 0": "Rook",
    "column 1": "Knight",
    "column 2": "Bishop",
    ...,
"row 1":
    "column 0": "Pawn",
    "column 1": "null",
    "column 2": "Pawn",
    ...,
"row 2":
    "column 0": "null",
    "column 1": "Pawn",
    "column 2": "null",
    ...

编辑:

我试过:

Gson gson = new 
GsonBuilder().setPrettyPrinting().serializeNulls().create();
    message = gson.toJson(piecesMatrix);

我得到:

SecurityException: Can not make a java.lang.reflect.Method constructor accessible

编辑II

我试过:

Gson gson = new GsonBuilder().setPrettyPrinting().serializeNulls().create();
    message = gson.toJson(piecesMatrix, Piece.class);

我得到:

    [ 10-07 00:28:20.591 10899:10899 D/Data = 

 ]
{}

1 回复 | 直到 6 年前

smatthewenglish 7 年前

是这样的吗。。。

        JSONArray arr = new JSONArray();
    for (int i = 0; i < piecesMatrix.length; i++) {
        JSONArray innerArray = new JSONArray();

        for (int j = 0; j < piecesMatrix[i].length; j++) {
            JSONObject column = new JSONObject();

            if (piecesMatrix[i][j] == null || piecesMatrix[i][j] instanceof LegalMove) {
                try {
                    column.put("column " + String.valueOf(j), null);
                } catch (Exception e) {}
            } else {
                try {
                    column.put("column " + String.valueOf(j), piecesMatrix[i][j].getClass().getSimpleName());
                } catch (Exception e) {}
            }
            innerArray.put(column);
        }
        JSONObject json = new JSONObject();
        try {
            json.put("row " + i, innerArray);
        } catch (JSONException e) {}
        arr.put(json);
    }

    Log.d("Data = \n\n", arr.toString());