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持久性查询中的异常

jpa java

Pradyut Bhattacharya · 技术社区 · 16 年前

java类中的代码

EntityManager em = null;
    EntityManagerFactory emf = null;

public List fname (String id) {
    String fname = null;
    List persons = null;
    try {
        emf = Persistence.createEntityManagerFactory("WebApplicationSecurityPU");
        em = emf.createEntityManager();
        persons = em.createQuery("select r from Roleuser r").getResultList();
        int i=0;
        for (i=0;i<persons.size(); i++)
            System.out.println("Testing n "+ i +" " + persons.get(i));

    } catch(Exception e) {
        System.out.println("" + e);
    }
    finally {
        if(em != null) {
            em.close();
        }
    }
    return persons;
}

IllegalArgumentException 完全的例外是

java.lang.IllegalArgumentException:一个创建文件时发生异常 EntityManager中的查询

我认为实体类没有初始化,或者它们没有与数据库连接这就是为什么

1 回复 | 直到 16 年前

Pradyut Bhattacharya 16 年前

我可以通过修改代码来纠正它

@PersistenceUnit
public EntityManagerFactory emf;
EntityManager em;


public List fname (String id) {
    String fname = null;
    List persons = null;
    //private PersistenceManagerFactory persistenceManagerFactory;

    try {
        emf = Persistence.createEntityManagerFactory("WebApplicationSecurityPU");

        em = emf.createEntityManager();
        persons = em.createQuery("select r from Roleuser r").getResultList();

        int i=0;
        for (i=0;i<persons.size(); i++)
            System.out.println("Testing n "+ i +" " + persons.get(i));

    } catch(Exception e) {
        System.out.println("" + e);
    }
    finally {
        if(em != null) {
            em.close();
        }
    }
    return persons;
}

谢谢

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