free是否从较小的结构指针中释放较大结构指针的所有内存?

#include "stdio.h"
#include "stdlib.h"

//testing for garbage collection

//base handler to ensure polymorphism
#define BASE char g;

struct temp {
  BASE
  short w;
};

struct femp {
  BASE
  short w;
  long d;
};


int main(void) {
  struct femp* first = malloc(sizeof(struct femp));
  first->d = 3444;
  struct temp* second = (struct temp*)first;
  free(second); // does this deallocate all the memory of first?
  free(first);
  return 0;
}

:如果第二个程序被释放,而不是第一个程序,则上述程序以非零状态退出。

结果:

7fb829d02000-7fb829d04000 rw-p 00000000 00:00 0 
7fb829d0c000-7fb829d10000 rw-p 00000000 00:00 0 
7fb829d10000-7fb829d11000 r--p 00023000 00:136 38                        /usr/lib/x86_64-linux-gnu/ld-2.24.so
7fb829d11000-7fb829d12000 rw-p 00024000 00:136 38                        /usr/lib/x86_64-linux-gnu/ld-2.24.so
7fb829d12000-7fb829d13000 rw-p 00000000 00:00 0 
7fffac407000-7fffac428000 rw-p 00000000 00:00 0                          [stack]
7fffac499000-7fffac49b000 r--p 00000000 00:00 0                          [vvar]
7fffac49b000-7fffac49d000 r-xp 00000000 00:00 0                          [vdso]
ffffffffff600000-ffffffffff601000 r-xp 00000000 00:00 0                  [vsyscall]
exited with non-zero status

free() 在指向一个较小的结构的指针上,它是从原始的malloc较大的结构转换而来的,仍然释放了所有内存?就像在我的代码中一样,释放第一个或第二个有什么区别吗?在释放之前,是否应该始终强制转换回原始类型?