如何在python run\u in\u executor方法调用中捕获异常

如何在使用run\u in\u执行器调用的run\u long\u thing()函数中引发异常? 它看起来像是被吞下了。我不需要阻塞代码中函数的结果。它基本上是一个fire-and-forget函数,但如果有任何异常,我仍然需要捕捉异常。。。

import asyncio
import time


def fire_and_forget(task, *args, **kwargs):
    loop = asyncio.get_event_loop()
    if callable(task):
        #if threadpoolworker is set to None,
        #the max_workers will default to the number of processors on the machine, multiplied by 5
        return loop.run_in_executor(None, task, *args, **kwargs)
    else:    
        raise TypeError('Task must be a callable.')


async def run_long_thing(sleep):
    print("Doing long thing... {:}".format(sleep))
    time.sleep(sleep)
    print("Done doing long thing. {:}".format(sleep))
    raise Exception("sh*t happens")


def do_it():
    print("Starting my main thing...")
    print("Calling my long thing...")
    for i in range(0,10,1):
        try:
            fire_and_forget(run_long_thing, i)
            print(i)
            print("Pom pi dom...")
            time.sleep(0.1)
            print("POOOOM Pom pi dom...")
        except:
            print("can i see the sh*t?")

do_it()