代码之家 › 专栏 › 技术社区 › Slyknight

如何使用QuillJs和body解析器提交表单?

quill body-parser forms node.js javascript

2

Slyknight · 技术社区 · 8 年前

我对Nodejs(和编码,一般来说)是新手。我正在尝试构建一个小型内容管理系统。我希望我的潜在最终用户能够设计他们的内容(粗体、斜体、超链接等)在点击按钮将帖子提交到我的博客之前。我在工具栏上看到的那种

以下是我在阅读了奎尔的指南之后得到的信息:

类型ejs公司

<style>
#editor {
  height: 300px;
}

</style>

<!-- Include Quill stylesheet -->
<link href="https://cdn.quilljs.com/1.0.0/quill.snow.css" rel="stylesheet">

<!-- Create the toolbar container -->
<div id="toolbar">
  <button class="ql-bold">Bold</button>
  <button class="ql-italic">Italic</button>
</div>

 <form action = '/blog' method = 'POST'>
  <!-- Create the editor container -->
  <input type = 'text' name = 'title' placeholder = 'title'>
  <label for="body">About me</label>
  <input name="body" type="hidden">
  <div id="editor">
     <p>I am at my wit's end. Stackoverflow is my last hope</p>
  </div>
    <button type="submit">Submit</button>

 </form>


<!-- Include the Quill library -->
<script src="https://cdn.quilljs.com/1.0.0/quill.js"></script>

<!-- Initialize Quill editor -->
<script>
  var editor = new Quill('#editor', {
    modules: { toolbar: '#toolbar' },
    theme: 'snow'
  });

  var form = document.querySelector('form');
  form.onsubmit = function() {
    console.log("hey")
    // Populate hidden form on submit
    var body = document.querySelector('input[name=body]');
    body.value = JSON.stringify(quill.getContents());

    console.log("Submitted", $(form).serialize(), $(form).serializeArray());

  };

</script>

应用程序。js文件

var app             = require('express')(),
    mongoose        = require('mongoose'),
    Blog            = require('./model/blog'),
    bodyParser      = require('body-parser');

mongoose.connect("mongodb://localhost/quill_demo", {useMongoClient:true});    
app.set('view engine','ejs'); //EJS WILL BE THE DEFAULT FILE THAT DISPLAYS THE FRONT-END DATA
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({extended:true})); // retrieve text from submitted forms from the EJS files. 

//Add new blog to the database
app.post('/blog', function(req, res){
    var myPost = {
        title:req.body.title,
        body: req.body.body
    };
    Blog.create(myPost, function(err, newBlog){
        if(err){
            console.log(err);
        } else {
            console.log("New Blog has been added");
            newBlog.save(function(err, savedBlog){
                if(err){
                    console.log(err);
                }else {
                    console.log(savedBlog);
                    res.redirect('/blog');
                }

            });
        }
    });

});

我在点击提交后检查数据库。“标题”字段工作正常。但在“body”字段中没有添加任何内容。

所以,看起来我少了几块。如果有任何帮助,我将不胜感激。如果有人简单地在我的代码中添加缺失的部分,我不会介意,稍后我将从他们的步骤中学习。

P、我没有CS学位。我自己学习。所以,尽量用外行的话回答

1 回复 | 直到 8 年前

1

2

Slyknight 8 年前

没关系,我想出来了!

我把剧本改成了这个,它帮了我。提交表单时调用该函数

<script>
  var editor = new Quill('#editor', {
      modules: { toolbar: "#toolbar" },
      theme: 'snow'
  });


  function formatField(){
    var editor = document.querySelector(".ql-editor").contentEditable = false;
    var clipboard = document.querySelector(".ql-clipboard").contentEditable = false;
    var bar = document.querySelector("input[type=text]").type="hidden"
    var p = document.querySelector("#editor");
    var myInput = document.querySelector("input[name=about]");
    myInput.value = p.innerHTML;
  }


</script>