如何从字符串中删除所有空白

>>> s = " \t foo \n bar "
>>> "".join(s.split())
'foobar'

>>> s.replace(" ", "")
'\tfoo\nbar'

$ python -m timeit '"".join(" \t foo \n bar ".split())'
1000000 loops, best of 3: 1.38 usec per loop
$ python -m timeit -s 'import re' 're.sub(r"\s+", "", " \t foo \n bar ")'
100000 loops, best of 3: 15.6 usec per loop

$ python -m timeit -s 'import re; e = re.compile(r"\s+")' 'e.sub("", " \t foo \n bar ")'
100000 loops, best of 3: 7.76 usec per loop

>>> import re
>>> re.sub(r'\s+', '', 'strip my spaces')
'stripmyspaces'

"strip my spaces".translate( None, string.whitespace )

"strip my spaces".translate(str.maketrans('', '', string.whitespace))

"foo bar\t".replace(" ", "").replace("\t", "")

import re
re.sub(r"\s", "", "foo bar\t")

string1="    This is Test String to strip leading space"
print string1
print string1.lstrip()

string2="This is Test String to strip trailing space     "
print string2
print string2.rstrip()

string3="    This is Test String to strip leading and trailing space      "
print string3
print string3.strip()

string4="   This is Test String to test all the spaces        "
print string4
print string4.replace(" ", "")

re.sub

\s in the manual

import re
re.sub(' ','','strip my spaces')

s = " \t foo \n bar "
"".join(s.split())
'foobar'

i=0
ProductList=[]
while i < len(new_list): 
   temp=''                            # new_list[i]=temp=' Plain   Utthapam  '
   #temp=new_list[i].strip()          #if we want o/p as: 'Plain Utthapam'
   temp="".join(new_list[i].split())  #o/p: 'PlainUtthapam' 
   temp=temp.upper()                  #o/p:'PLAINUTTHAPAM' 
   ProductList.append(temp)
   i=i+2

def remove_spaces(in_string: str):
    return in_string.translate(str.maketrans({' ': ''})

import string
def remove_whitespace(in_string: str):
    return in_string.translate(str.maketrans(dict.fromkeys(string.whitespace)))

str.translate Full documentation for str.translate

str.maketrans str Full documentation for str.maketrans

string string.whitespace Full documentation for string

dict.fromkeys None Full documentation for dict.fromkeys

split/join translate

>>> import string
>>> ws = set(string.whitespace)

filter

>>> "".join(filter(lambda c: c not in ws, "strip my spaces"))
'stripmyspaces'

>>> import string
>>> "".join([c for c in "strip my spaces" if c not in ws])
'stripmyspaces'

>>> import functools
>>> "".join(functools.reduce(lambda acc, c: acc if c in ws else acc+c, "strip my spaces"))
'stripmyspaces'

>>> from timeit import timeit
>>> timeit('"".join("strip my spaces".split())')
0.17734256500003198
>>> timeit('"strip my spaces".translate(ws_dict)', 'import string; ws_dict = {ord(ws):None for ws in string.whitespace}')
0.457635745999994
>>> timeit('re.sub(r"\s+", "", "strip my spaces")', 'import re')
1.017787621000025

>>> SETUP = 'import string, operator, functools, itertools; ws = set(string.whitespace)'
>>> timeit('"".join([c for c in "strip my spaces" if c not in ws])', SETUP)
0.6484303600000203
>>> timeit('"".join(c for c in "strip my spaces" if c not in ws)', SETUP)
0.950212219999969
>>> timeit('"".join(filter(lambda c: c not in ws, "strip my spaces"))', SETUP)
1.3164566040000523
>>> timeit('"".join(functools.reduce(lambda acc, c: acc if c in ws else acc+c, "strip my spaces"))', SETUP)
1.6947649049999995