如何使回文函数不检查int,从而告诉它要读取的总行数[duplicate]

我用的是 Scanner 方法 nextInt() 和 nextLine() 用于读取输入。

看起来是这样的:

System.out.println("Enter numerical value");    
int option;
option = input.nextInt(); // Read numerical value from input
System.out.println("Enter 1st string"); 
String string1 = input.nextLine(); // Read 1st string (this is skipped)
System.out.println("Enter 2nd string");
String string2 = input.nextLine(); // Read 2nd string (this appears right after reading numerical value)

问题是,在输入数值后 input.nextLine() 跳过第二个 输入nextLine() 执行,因此我的输出如下所示:

Enter numerical value
3   // This is my input
Enter 1st string    // The program is supposed to stop here and wait for my input, but is skipped
Enter 2nd string    // ...and this line is executed and waits for my input

我测试了我的应用程序,看起来问题在于使用 input.nextInt() .如果我删除它,那么两个 string1 = input.nextLine() 和 string2 = input.nextLine() 按照我的要求执行。