你好,伙计们,如果你觉得这个问题很愚蠢,很抱歉。
我有3个表:货币(ID名称)语言(ID名称描述)交易(ID金额语言ID货币ID)
因此,我希望插入到事务中,但要确保它不会插入未知的语言或货币(这意味着如果没有现有的父语言和货币,则不应插入到messagetemplate)
这是我的映射文件
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="com.myproject.model">
<class name="Transaction" table="transaction">
<id name="id">
<generator class="native"/>
</id>
<property column="amount" name="amount" type="String"/>
<many-to-one class="CurrencyImpl" column="currency" name="currency"/>
<many-to-one class="LanguageImpl" column="language" name="language"/>
</class>
</hibernate-mapping>
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="com.myproject.model">
<class name="Currency" table="currency">
<id name="id">
<generator class="native"/>
</id>
<property column="currency_name" name="name" type="String"/>
</class>
</hibernate-mapping>
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="com.myproject.model">
<class name="Language" table="language">
<id name="id">
<generator class="native"/>
</id>
<property column="language_name" name="name" type="String"/>
<property column="language_description" name="description" type="String"/>
</class>
</hibernate-mapping>
在当前的映射中,情况似乎并非如此。如何实现这一点?谢谢你的阅读