如何在python中组合元组

是的,这是可能的

from itertools import product
for i in range(your_limit):
    your_tuples_container.append(your_new_tuple)
    result = list(product(*your_tuples_container))

试试看 product

from itertools import product
a = (1, 2),(5, 6) ,(3, 4)
result = list(product(*a))

可以使用递归,因此只需要几个 for 任何输入维度的循环:

l = [(1, 2), (5, 6), (3, 4)]
def cartesian_product(d, current = []):
  if not d[1:]:
    yield [i+[b] for i in current for b in d[0]]
  else:
    yield from cartesian_product(d[1:], [i+[b] for i in current for b in d[0]])

print(list(cartesian_product(l[1:], list(map(lambda x:[x], l[0]))))[0])

输出:

[[1, 5, 3], [1, 5, 4], [1, 6, 3], [1, 6, 4], [2, 5, 3], [2, 5, 4], [2, 6, 3], [2, 6, 4]]