下一个问题

好吧,这整晚都在折磨我,我是说,我已经花了至少8个小时的时间编写这个代码了。这有什么问题,阿格。

我正在尝试更新所有 <span id="column_[row index number]_[column index number]_[layout position number]"> 增加一个直到下一个 id="row_[row index number]" tr element ,它应该搜索的tr元素的ID为 tr_[row index number]_[column index number]_[layout position number] 但对某些上帝知道什么原因,它给了我一些问题。它也在更新 <span> 标记2X,这将它从所需的值更改为1,比它应该的值多…只有 1 <span> 标签内 firstChild <td> element 每一个 <tr> elements . 我只是不明白为什么它只为其中的一个设置了2X,而且它似乎是随机的或者什么的。ARGGGG。

只有1 <SPAN & GT; 元素在 <td id="tdcolumn_[row index number]_[column index number]_[layout position number]> 标签,但出于某种原因,它两次调用同一个标签。它应该只叫一次。阿格格我不明白为什么??

这是我的密码,有人请帮我…

// Reorder all columns, if any, in the other rows after this 1.
if (aRowId != 0 && lId.indexOf("tr_" + aRowId) == 0 && rowComplete != aRowId)
{
    var tempTr = lTable.childNodes[i].childNodes[p];


    while(tempTr.nodeType == 1 && tempTr.nextSibling != null)
    {
        var tempId = tempTr.getAttribute("id");

        if (!tempId) continue;

        if (tempId.indexOf("row_") == 0)
        {
            // All done this row, set it to completed!
            rowComplete = aRowId;
            break;
        }

        if (tempTr.hasChildNodes)
        {

            var doneChilds = false;

            // grab the id where tdcolumn_{aRowId}.indexOf = 0.
            for (fcTd = 0; fcTd<tempTr.childNodes.length; fcTd++)
            {
                if (tempTr.childNodes[fcTd].nodeName == '#text') continue;

                var tempfcId = tempTr.childNodes[fcTd].getAttribute("id");

                if (!tempfcId) continue;

                if (tempfcId.indexOf("tdcolumn_" + aRowId) != 0) continue;

                // looping through the children in the <td> element here.
                if (tempTr.childNodes[fcTd].hasChildNodes)
                {
                    for (x = tempTr.childNodes[fcTd].childNodes.length-1; x>0; x--)
                    {
                        if (tempTr.childNodes[fcTd].childNodes[x].nodeName == '#text') continue;

                        var tempSpanId = tempTr.childNodes[fcTd].childNodes[x].getAttribute("id");

                        if (!tempSpanId) continue;

                        if (tempSpanId.indexOf("column_") != 0) 
                            continue;

                        // alert(tempSpanId);

                        alert(tempTr.childNodes[fcTd].childNodes[x].nodeName);

                        var tSpanId = new Array();
                        tSpanId = tempSpanId.split("_");

                        if (currColumnId == 0)
                        {
                            currColumnId = parseInt(tSpanId[1]);
                            var incCol = currColumnId;  
                        }

                        incCol++;

                        // alert("currColumnId = " + currColumnId + "\n\ntSpanId[1] = " + tSpanId[1] + "\n\nincCol = " + incCol);

                        // Set the new Id's and Text, after which we can exit the for loop.
                        tempTr.childNodes[fcTd].childNodes[x].setAttribute("id", "column_" + incCol);
                        tempTr.childNodes[fcTd].childNodes[x].setAttribute("class", "dp_edit_column");
                        tempTr.childNodes[fcTd].childNodes[x].innerHTML = oColumnText + " " + incCol;
                        // tempTr.childNodes[fcTd].setAttribute("id", "tdcolumn_" + aRowId + "_" + (parseInt(tSpanId[1])+1) + "_" + tSpanId[3]);

                        doneChilds = true;

                        break;
                    }
                }
                else
                    continue;

                if (doneChilds == true)
                    continue;
            }
        }
        else
            continue;

        tempTr = tempTr.nextSibling;
    }
}

请帮帮我,谢谢:)