将函数返回作为参数传递给另一个函数

如何获取用户在函数中输入的列表 take_list() 并将其传递给函数 no_duplication() ?

在线路上: no_duplication(k)

def take_list():
    k = []
    i = 0
    list_length = int(input("how many elements your list has ? \n "))
    while i < list_length:
        element = int(input("enter you list elements : "))
        k.append(element)
        i += 1
    print(k, "  is your list")
    return k

def no_duplication(k):
    k = set(k)
    k = list(k)
    print(k, " Your list without duplications")
 

take_list()
no_duplication(k)