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为什么if/else语句不能在我的函数中工作?

definition main if-statement function python

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Francis Bradley · 技术社区 · 8 年前

我使用if/else语句让用户选择客户选项(居民或企业),输入他们使用的千瓦数,然后程序将计算电费。这必须在函数中使用(我们在课堂上学习的一章)。这是我的代码:

def main():
    customer = input("Enter R for residential or B for business")
    hours = int(input("Enter number of khw"))
    bill_calculator(hours, customer)


def bill_calculator(kwh,customer):
    if customer == 'R' :
        if kwh < 500:
            normal_amount = kwh * .12
        print ("Please pay this amount: ", normal_amount)
    elif kwh > 500:
        over_amount = kwh * .15
        print("Please pay this amount",over_amount)

    if customer == 'B':
        if kwh < 800:
            business_amount = kwh * .16
        print("Please pay this amount: ")
    elif kwh > 800:
        business_amount = kwh * .2
    print("Please pay this amount,", business_amount)

    main()

我的“常驻”计算工作并显示,但“业务”计算不工作。我觉得这和我的压痕有关,但我不知道在哪里。

下面是我的错误:

Enter R for residential or B for businessR
Enter number of khw77
Please pay this amount:  9.24
Traceback (most recent call last):
  File "C:/Users/vanbe/PycharmProjects/Lesson7/L07P2.py", line 24, in <module>
    main()
  File "C:/Users/vanbe/PycharmProjects/Lesson7/L07P2.py", line 4, in main
    bill_calculator(hours, customer)
  File "C:/Users/vanbe/PycharmProjects/Lesson7/L07P2.py", line 22, in bill_calculator
    print("Please pay this amount,", business_amount)
UnboundLocalError: local variable 'business_amount' referenced before assignment

谢谢大家

1 回复 | 直到 8 年前

Brad Dre 8 年前

您的代码至少有三个问题。首先,作为juanpa。arrivillaga在评论中提到,您在任何情况下都在打印business\u金额,但仅在客户==“B”时分配

其次,如果“R”客户的kwh等于500,而“B”客户的kwh等于800,则不需要进行分配。

最后,它看起来像elif kwh>500意味着与kwh处于同一水平<500

您可能希望您的代码如下所示:

    if customer == 'R' :
        if kwh < 500:
            normal_amount = kwh * .12
            print ("Please pay this amount: ", normal_amount)
        elif kwh >= 500:
            over_amount = kwh * .15
            print("Please pay this amount",over_amount)

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