Python BeautifulSoup解析HTML时出错

这项工作(:

from bs4 import BeautifulSoup

html = """<table style="padding-top:10px;">
    <tr><th>ISP:</th><td>Brighthouse Networks</td></tr>
    <tr><th>Services:</th><td><a href="/ip-services">None Detected</a></td></tr>
    <tr><th>City:</th><td>Miami</td></tr>
    <th>Region:</th><td>Florida</td>
    <tr><th>Country:</th><td>United States</td></tr>
</table>"""

soup = BeautifulSoup(html)
table = soup.findAll('table', {"style":"padding-top:10px;"})[0]

trs = table('tr')
for tr in trs:
    print tr.th.text,
    print tr.td.text

#and this for the 'Region'
print table("th")[3].text,
print table("td")[3].text

输出:

ISP: Brighthouse Networks
Services: None Detected
City: Miami
Country: United States
Region: Florida

table = soup.find_all('table',attrs={'style':'padding-top:10px;'})

应该会成功。

find_all() 具有以下签名:

find_all(name, attrs, recursive, text, limit, **kwargs)

若将属性作为第二个参数传递,find_all希望它是字符串而不是字典。如果要将属性字典传递给find_all,则应将其传递为 attrs keyword argument .