作为jQuery选择器的字符串数组?

["#p1", "#p2", "#p3", "#p4", "#p5"].join(", ")

可以选择元素数组,问题是您还没有元素,只有选择器字符串。无论以何种方式分割,都必须执行.getElementById之类的搜索或使用实际的jQuery选择。

Array.join method

var a = ["#p1", "#p2", "#p3", "#p4", "#p5"];
var s = a.join(", ");
//s should now be "#p1, #p2, #p3, ..."
$(s).whateverYouWant();

$(foo.join(", "))

$(theArray.join(','));

//If this is only one use variable you can use
$(['#p1','#p2','#p3','#p4','#p5'].join(',')).methodToUse();
//if you DO need it as a variable you can
var joined = ['#p1','#p2','#p3','#p4','#p5'].join(',');
$(joined).methodsToUse();

如果你想让他们单独做某事,还有.each();

var peas = ['#p1','#p2','#p3','#p4','#p5'];
$.each(peas, i => {
    $(peas[i]).click(() => {
        $(peas[i]).css({'color':'red'});
    });
});

$.each(array, function(i){
    // any code you wish as long as you have an array selector
    //$(array[i]).whatever function
});

var peas = ['#p1','#p2','#p3','#p4','#p5'],
    poppy=(v,i)=>peas.toString().replace(`,${v[i]}`,'').replace(`${v[i]},`,'');

(// get each pea index
  $.each(peas,i=>///funciton(i){ code inside}

    (//set up each individual index's functions
      $('.peastock').append(`<p id="p${[i+1]}">I am ${peas[i]}</p>`),
      $(peas[i]).click(()=>(
        $(peas[i]).css({"color":"red","background-color":"rgba(128,0,0,0.1)"}),
        $(poppy(peas,i)).css({'color':'black','background-color':'rgba(255,255,255,0.2)'}))))),

  $('.peastock').append(`
    <div id="ree">ES6 isnt suitable for all of jQuery's usage!</div>
    <div>Since some functions inside of jQuery's methods dont require 'this' or 'return'</div>
    <div>You can learn this by going <a href="https://www.w3schools.com/Js/js_es6.asp">here</a></div>
  `),
  $("*").css({"margin":"0 auto","padding":"1%"}),
  $("* .peastock, .peastock, .peastock *").css({"background-color":"rgba(128,0,0,0.1)"})
);

jQuery .each() The fiddle in action (with updates!)

join

var arr = ["#p1", "#p2", "#p3", "#p4", "#p5"];
$(arr.join(","))

["#p1", "#p2", "#p3", "#p4", "#p5"].toString()