以下查询(cqlsh cassandra)
SELECT * from keyspace.dialogs WHERE sid = "07323067ef605ffdb4fa" ;
给我这个错误
SyntaxException: line 1:92 no viable alternative at input ';' (...keyspace.dialogs WHERE sid = ["07323067ef605ffdb4fa" ;)
sid键正确,数据应该存在,语法与cqlsh不同吗?
将singlequote用于txt:
SELECT * from keyspace.dialogs WHERE sid = '07323067ef605ffdb4fa' ;