fileinput.input()
接受交互式输入。
我看了一下上面的代码-
https://github.com/python/cpython/blob/master/Lib/fileinput.py
这就是内线阅读器的外观:
def _readline(self):
if not self._files:
if 'b' in self._mode:
return b''
else:
return ''
self._filename = self._files[0]
self._files = self._files[1:]
self._startlineno = self.lineno()
self._filelineno = 0
self._file = None
self._isstdin = False
self._backupfilename = 0
if self._filename == '-':
self._filename = '<stdin>'
if 'b' in self._mode:
self._file = getattr(sys.stdin, 'buffer', sys.stdin)
else:
self._file = sys.stdin
self._isstdin = True
else:
if self._inplace:
self._backupfilename = (
os.fspath(self._filename) + (self._backup or ".bak"))
try:
os.unlink(self._backupfilename)
except OSError:
pass
# The next few lines may raise OSError
os.rename(self._filename, self._backupfilename)
self._file = open(self._backupfilename, self._mode)
try:
perm = os.fstat(self._file.fileno()).st_mode
except OSError:
self._output = open(self._filename, "w")
else:
mode = os.O_CREAT | os.O_WRONLY | os.O_TRUNC
if hasattr(os, 'O_BINARY'):
mode |= os.O_BINARY
fd = os.open(self._filename, mode, perm)
self._output = os.fdopen(fd, "w")
try:
if hasattr(os, 'chmod'):
os.chmod(self._filename, perm)
except OSError:
pass
self._savestdout = sys.stdout
sys.stdout = self._output
else:
# This may raise OSError
if self._openhook:
self._file = self._openhook(self._filename, self._mode)
else:
self._file = open(self._filename, self._mode)
self._readline = self._file.readline # hide FileInput._readline
return self._readline()
我不知道该怎么做,我很想知道这里的交互输入实际上是如何处理的,因为我没有看到对内置的调用
input()
.
实际上是什么在中生成了用户提示
文件输入。输入()
?
