如何在Java中格式化日期范围?

JodaTime ,是用Java处理日期的最佳库(上次我检查时)。格式很简单,毫无疑问可以通过使用自定义的DateFormatter实现来改进。这也会检查年份是否相同,但不会输出年份,这可能会造成混淆。

import org.joda.time.DateTime;

public class DateFormatterTest {

    public static void main(String[] args) {

        DateTime august23rd = new DateTime(2010, 8, 23, 0, 0, 0, 0);
        DateTime august25th = new DateTime(2010, 8, 25, 0, 0, 0, 0);
        DateTime september5th = new DateTime(2010, 9, 5, 0, 0, 0, 0);

        DateFormatterTest tester = new DateFormatterTest();
        tester.outputDate(august23rd, august25th);
        tester.outputDate(august23rd, september5th);

    }

    private void outputDate(DateTime firstDate, DateTime secondDate) {
        if ((firstDate.getMonthOfYear() == secondDate.getMonthOfYear()) && (firstDate.getYear() == secondDate.getYear())) {
            System.out.println(firstDate.getDayOfMonth() + " - " + secondDate.getDayOfMonth() + " " + firstDate.monthOfYear().getAsShortText());
        } else {
            System.out.println(firstDate.getDayOfMonth() + " " + firstDate.monthOfYear().getAsShortText() + " - " + secondDate.getDayOfMonth() + " " + secondDate.monthOfYear().getAsShortText());
        }
    }
}

输出:

8月23日至25日

public final class DateUtility
{
    public static final DateTimeFormat MONTH_FORMAT = DateTimeFormat.getFormat("MMM");
    public static final DateTimeFormat DAY_FORMAT = DateTimeFormat.getFormat("dd");
    public static final DateTimeFormat DAY_MONTH_FORMAT = DateTimeFormat.getFormat("dd MMM");

    public static final String DASH = " - ";

    /**
     * Returns a "collapsed" date range String representing the period of time
     * between two Date parameters. Example: August 19 as a {@code startDate}
     * and August 30 as an {@code endDate} will return "19 - 30 AUG", August 28
     * as a {@code startDate} and September 7 as an {@code endDate} will return
     * "28 AUG - 07 SEP". This means if you pass this two dates which cannot
     * collapse into a shorter form, then the longer form is returned.  Years
     * are ignored, and the start and end dates are not checked to ensure we
     * are not going backwards in time (Aug 10 - July 04 is not checked).
     * 
     * @param startDate
     *            the start Date in the range.
     * @param endDate
     *            the end Date in the range.
     * @return a String representation of the range between the two dates given.
     */
    public static String collapseDate(Date startDate, Date endDate) {
        String formattedDateRange;

        // Get a comparison result to determine if the Months are the same
        String startDateMonth = MONTH_FORMAT.format(startDate);
        String endDateMonth = MONTH_FORMAT.format(endDate);

        if (startDateMonth.equals(endDateMonth))
        {
            formattedDateRange = DAY_FORMAT.format(startDate) + DASH
                    + DAY_MONTH_FORMAT.format(endDate).toUpperCase();
        }
        else
        {
            // Months don't match, split the string across both months
            formattedDateRange = DAY_MONTH_FORMAT.format(startDate).toUpperCase()
                    + DASH + DAY_MONTH_FORMAT.format(endDate).toUpperCase();
        }
        return formattedDateRange;
    }
}

签出java的 SimpleDateFormat 班级。您可以构造一个SimpleDataFormat,将您的日期模式作为字符串传递。

为了补充Jeroen的答案,您将使用SimpleDateFormat两次,范围的每一端使用一次。

默认情况下,Java中没有day range这样的类型,因此没有任何DateFormats应用于这种情况的字符串表示。

在我看来,最好是创建TimeSpan或TimeDiff类型,并将方法重写为string。或者像你建议的那样,如果你需要两个,也可以创建一个DateFormmater。