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计算两个日期之间的差值

date javascript

joe · 技术社区 · 17 年前

我试过这样做

<script type="text/javascript">
     var date2=02/09/2009;
     var date1=03/12/2009;
     var diff = date1.getDate()-date2.getDate();
     alert (diff);

</script>

但它不起作用,这是原因吗 getDate 将只适用于 Date ?

如何找出这两个日期之间的差异?我是否无法使用此函数,因为我正在salesforce CRM apex页面中添加javascript?

<script type="text/javascript">
     var date2= new Date ("02/09/2009");
     var date1= new Date ("04/09/2009");
     var diff = date1.getDate()-date2.getDate();
     alert (diff);

</script>

编辑2:它不工作太。。。

<script type="text/javascript">
     var date2= "02/09/2009";
     var date1= "04/09/2009";
     var diff2 =    new Date(Date.parse("03/12/2009")-
                        Date.parse("02/09/2009")).toLocaleDateString();

//var new_date=新日期(1970年1月1日); //var diff3=diff2.getDate(); 警报(diff2);

</script>

10 回复 | 直到 17 年前

Robert L 17 年前


<script language="JavaScript">
<!--
function dstrToUTC(ds) {
 var dsarr = ds.split("/");
 var mm = parseInt(dsarr[0],10);
 var dd = parseInt(dsarr[1],10);
 var yy = parseInt(dsarr[2],10);
 return Date.UTC(yy,mm-1,dd,0,0,0);
}

function datediff(ds1,ds2) {
 var d1 = dstrToUTC(ds1);
 var d2 = dstrToUTC(ds2);
 var oneday = 86400000;
 return (d2-d1) / oneday;
}

// test cases are below

var a; var b;

a = "01/09/1999";
b = "01/10/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/12/1999";
b = "01/19/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/19/1999";
b = "01/12/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/03/1999";
b = "01/13/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "04/30/1999";
b = "05/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "05/30/1999";
b = "06/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "02/28/1999";
b = "03/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "02/28/2000";
b = "03/01/2000";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/01/1999";
b = "12/31/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/01/2000";
b = "12/31/2000";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "12/15/1999";
b = "01/15/2001";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

// -->
</script>

RameshVel 17 年前

date2=02/09/2009不被视为日期。它是这样工作的。首先,它划分为02/09,返回0.22222,然后除以2009(0.22222/2009)。最后您得到了一个结果date2=0.00011063510314695。与计算date1的结果的方式相同。

使用new Date()或Date.parse(“02/09/2009”)

编辑:

   new Date(Date.parse("03/12/2009")-Date.parse("02/09/2009")).toLocaleDateString() Or
   new Date(date1- date2).toLocaleDateString()

那不管用吗。。??

编辑:

也许这行得通。。你能试试这个吗。。

 Date.parse("03/12/2009")-Date.parse("02/09/2009") / (24*60*60*1000)

它会在31天内返回

这似乎对我有用。。但在我的时区,2009年12月3日是2009年第3个月第11天

SilentGhost 17 年前

getDate Date 对象正如任何文档明确指出的那样,它返回的日期范围为0到31。如果不是同一个月,尝试从另一个中减去一个是没有意义的。

bogdanbrudiu 17 年前

diff.setTime(Math.abs(date1.getTime() - date2.getTime()));

timediff = diff.getTime();

weeks = Math.floor(timediff / (1000 * 60 * 60 * 24 * 7));
timediff -= weeks * (1000 * 60 * 60 * 24 * 7);

days = Math.floor(timediff / (1000 * 60 * 60 * 24)); 
timediff -= days * (1000 * 60 * 60 * 24);

hours = Math.floor(timediff / (1000 * 60 * 60)); 
timediff -= hours * (1000 * 60 * 60);

mins = Math.floor(timediff / (1000 * 60)); 
timediff -= mins * (1000 * 60);

secs = Math.floor(timediff / 1000); 
timediff -= secs * 1000;

alert(weeks + " weeks, " + days + " days, " + hours + " hours, " + mins + " minutes, and " + secs + " seconds");

Khodor 17 年前

Residuum 17 年前

getDate()返回日期一个月,在你的情况下:9和12。
您应该通过以下方式明确定义日期对象。月份是以0为基础的,因此0=一月,1=二月。。。
这些是数字,不是字符串。如果要使用字符串作为日期,则需要完全相同的格式,没有任何内容是可选的:

var newDate=新日期(“月日,年时:分:秒”); var date2=新日期(“2009年2月9日00:00:00”);

<script type="text/javascript">
    function daysFromString(dateString)
    {
        // split strings at / and return array
        var splittedString = dateString.split("/");
        // make a new date. Caveat: Months are 0-based in JS
        var newDate = new Date(parseInt(splittedString[2], 10), parseInt(splittedString[0], 10)-1, parseInt(splittedString[1], 10));
        // returns days since jan 1 1970
        return Math.round(newDate.getTime() / (24*3600*1000));
    }

    var dateString2 = "02/09/2009";
    var dateString1= "03/12/2009";
    var dateDays1 = daysFromString(dateString1);
    var dateDays2 = daysFromString(dateString2);
    var diff = dateDays1 - dateDays2;
    alert (diff);
</script>

dmateev 17 年前

Here 解释了如何在javascript中查找两个日期之间的差异

Pier Luigi 17 年前

你必须使用日期对象,像这样

var d = new Date(2009,9,19); //19th october, months are 0-based
var d2 = new Date(2009,10,12);
var diff = (d2 - d)/60000;  //diff in minutes
alert(diff / 24);   //difference in hours

Elias Zamaria 17 年前

var diff2 =    Date.parse("03/12/2009") - Date.parse("02/09/2009");

它将以毫秒为单位显示日期之间的差异。将这个数字除以86400000,差额将以天为单位。

-1

rahul 17 年前

<script type="text/javascript">
function GetD()
{
    var date1 = new Date ( 2009 , 09 , 02 );
    var date2 = new Date ( 2009 , 12 , 03 );        

    var diff = days_between (date1,date2);
    alert ( diff );
}
function days_between(date1, date2) {

    // The number of milliseconds in one day
    var ONE_DAY = 1000 * 60 * 60 * 24;

    // Convert both dates to milliseconds
    var date1_ms = date1.getTime();
    var date2_ms = date2.getTime();

    // Calculate the difference in milliseconds
    var difference_ms = Math.abs(date1_ms - date2_ms);

    // Convert back to days and return

    return Math.round(difference_ms/ONE_DAY);
}
</script>