在开发OOJ时,我应该引用原型函数还是变量版本?

你一定要用

this.showMessage("msg");

第二个版本根本无法正常工作。为什么?因为调用 showMessage 将导致其“this”变量指向原型对象,而不是实例。这几乎肯定不是你想要的。

如果您想要一个实例方法,您应该使用这个.*引用。否则,如果要使用类方法,可以使用以下方法:

//starting off
Foo = function() {
};

Foo.prototype.ShowMessage = function(msg) {
    alert("Instance message: " + msg);
};

Foo.ShowMessage = function(msg) {
    alert("Class message: " + msg);
};

Foo.prototype.Validate = function(msg) {
    //some validation stuff...
    if (!Valid) {
        this.ShowMessage("Please check your inputs, there seems to be a problem with them.");
        Foo.ShowMessage("Please check your inputs, there seems to be a problem with them.");
    }
};