在python中排序

>>> results=[{"s":1,"score":100},{"s":2,"score":101},{"s":3,"score":99},{"s":4,"score":1},{"s":5,"score":1000}]

>>> from operator import itemgetter

>>> sorted(results, key=itemgetter("score"))
[{'s': 4, 'score': 1}, {'s': 3, 'score': 99}, {'s': 1, 'score': 100}, {'s': 2, 'score': 101}, {'s': 5, 'score': 1000}]

您可以使用如下自定义比较函数对其进行排序:

results.sort(key=lambda x:x['score'])

你可以使用 sorted 具有 operator.itemgetter 要使用“得分”值作为键:

sorted_results = sorted(results,key=operator.itemgetter("score"))

假设你的 results 是一个 dict (因为你称之为散列图,我猜 tweet_id 是字典键,而不是计数器),您需要先将其转换为列表才能对其进行排序。在Python 3中:

results = {}
results["1234"] = {"score": 123, "tweet": "Hello"}
results["4321"] = {"score": 321, "tweet": "there"}
results["abcd"] = {"score": 111, "tweet": "sailor!"}
l=[]
for key, value in results.items():    # use .iteritems() in Python 2.x
    l.append([key, value])

for item in sorted(l, key=lambda x: x[1]["score"]):
    print(item)

意志输出

['abcd', {'tweet': 'sailor!', 'score': 111}]
['1234', {'tweet': 'Hello', 'score': 123}]
['4321', {'tweet': 'there', 'score': 321}]