这是我第一次真正深入Python类,所以请原谅对术语的任何误用。
Factory Pattern
基于用户提供的URL动态选择子类的方法。以下是我的设置:
import requests
from bs4 import BeautifulSoup as BS
class Templates(object):
def __init__(self, url):
self.headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:54.0) Gecko/20100101 Firefox/54.0'}
self.url = url
def url(self):
return self.url
def response(self):
return self.response
def text(self):
return self.text
def dom(self):
return self.dom
@staticmethod
def get_template(url):
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:54.0) Gecko/20100101 Firefox/54.0'}
response = requests.get(url, headers=headers)
text = response.text
if 'Website by Dealer.com' in text:
return Dealer(url)
else:
return None
class Dealer(Templates):
def __init__(self, url):
Templates.__init__(self, url)
self.new_vehicle_url = "{}/new-inventory/index.htm".format(self.url.rstrip('/'))
self.used_vehicle_url = "{}/used-inventory/index.htm".format(self.url.rstrip('/'))
我想做的是打电话
Templates.get_template(url)
This question
使它看起来非常简单,但我在这个过程中遗漏了一些东西,因为我还想在我的
Templates
url
到
Template
什么是Pythonic方式来设置它,以使下面的代码能够工作?
template = Templates().get_template(url) # assume returns Dealer()
template.url
# 'http://www.some-website.com'
template.response.status_code
# 200