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如何获取所有子目录并返回它们的路径?

node.js-fs javascript

0

user3142695 · 技术社区 · 3 年前

假设存在以下文件夹结构:

/apps
|- /group1
|  |- /project1
|  |- /project2
|- /group2
|  |- /project3
|  |- /project4

我需要获得所有项目的路径,这些项目都是两级的(组文件夹和项目文件夹)。

所以我从这个开始:

import { readdirSync } from 'fs'

const directoriesInDirectory = readdirSync([rootPath, 'apps'].join('/'), {
  withFileTypes: true
})
.filter((item) => item.isDirectory())
.map((item) => item.name)

这给了我所有的小组 ['group1', 'group2'] .

但我需要明白:

[
    'apps/group1/project1',
    'apps/group1/project2',
    'apps/group2/project3',
    'apps/group2/project4'
]

2 回复 | 直到 3 年前

1

0

code 3 年前

你需要表演 readdirSync 多次,一次用于 app 目录,其余为嵌套目录。此外,如果您调整了非阻塞特性,则可以使用promise,而不是使用sync:

import { readdir } from 'fs/promises'

const startPath = [rootPath, 'apps'].join('/')

const parentDirs = (
  await readdir(startPath, {
    withFileTypes: true,
  })
)
  .filter((item) => item.isDirectory())
  .map((item) => item.name)

const projectPaths = (
  await Promise.all(
    parentDirs.map(async (dir) => {
      const projects = (
        await readdir(startPath + '/' + dir, {
          withFileTypes: true,
        })
      )
        .filter((item) => item.isDirectory())
        .map((item) => item.name)
      return { dir, projects }
    })
  )
)
  .map(({ dir, projects }) =>
    projects.map((project) => [startPath, dir, projects].join('/'))
  )
  .flat()

console.log(projectPaths) // ['apps/group1/project1', 'apps/group1/project2', ...]

2

0

cqb13 3 年前

我相信这段代码应该能满足你的需求,我不知道如果你添加更多的子目录,它会有多好,我做了有限的测试,但它应该可以正常工作。

const fs = require("fs");
const path = require("path");

function getSubdirectories(rootPath) {
  const result = [];

  const directoriesInDirectory = fs
    .readdirSync(rootPath, {
      withFileTypes: true
    })
    .filter(item => item.isDirectory())
    .map(item => item.name);

  directoriesInDirectory.forEach(dir => {
    const subdirectories = getSubdirectories(path.join(rootPath, dir));
    // for each directory in the root directory, check if it has subdirectories
    if (subdirectories.length > 0) {
      subdirectories.forEach(subdir => {
        result.push(path.join(dir, subdir));
      });
    } else {
      result.push(dir);
    }
  });

  return result;
}

const subdirectories = getSubdirectories("./app");

const subdirectoryPaths = subdirectories.map(subdir => {
  return path.join("app", subdir);
});

console.log(subdirectoryPaths);