当BulkWriteError发生时Pymango初始化了ID

我知道我们可以 inserted_ids pymongo.results.InsertManyResult 退回人 insert_many

>>> o = db.collection.insert_many([{"hash": "abcde"}, {"hash": "efgh"}], ordered=False)
>>> o.inserted_ids
   [ObjectId('5f5280fdca7d7735e9dcbb85'), ObjectId('5f5280fdca7d7735e9dcbb86')]

但让我们考虑一下 unique index "hash" 复制 已插入的唯一字段,该字段将导致预期的 例外情况 BulkWriteError

>>> try:
        o = db.collection.insert_many([{"hash": "efgh"}, {"hash": "ijk"}], ordered=False)
    except BulkWriteError as e:
        print(e.details)
    
    {'nInserted': 1,
     'nMatched': 0,
     'nModified': 0,
     'nRemoved': 0,
     'nUpserted': 0,
     'upserted': [],
     'writeConcernErrors': [],
     'writeErrors': [{'code': 11000,
                     'errmsg': 'E11000 duplicate key error collection: '
                               'db.collection index: hash_1 dup key: { : "efgh" }',
                     'index': 0,
                     'op': {'_id': ObjectId('5f52814381c45515348fd36b'),
                            'hash': 'efgh'}}]}

'nInserted' ) ?