如何获取lxml中元素的路径?

使用 getpath 从elementtree对象。

from lxml import etree

root = etree.fromstring('<foo><bar>Data</bar><bar><baz>data</baz>'
                        '<baz>data</baz></bar></foo>')

tree = etree.ElementTree(root)
for e in root.iter():
    print tree.getpath(e)

印刷品

/foo
/foo/bar[1]
/foo/bar[2]
/foo/bar[2]/baz[1]
/foo/bar[2]/baz[2]

见 Xpath and XSLT with lxml from the lxml documentation 这将给出包含文本的元素的路径

一个例子是

import cStringIO
from lxml import etree

f = cStringIO.StringIO('<foo><bar><x1>hello</x1><x1>world</x1></bar></foo>')
tree = lxml.etree.parse(f)
find_text = etree.XPath("//text()")

# and print out the required data
print [tree.getpath( text.getparent()) for text in find_text(tree)]

# answer I get is 
>>> ['/foo/bar/x1[1]', '/foo/bar/x1[2]']

root = etree.parse(open('tmp.txt'))

for e in root.iter():
    print root.getpath(e)

如果代码部分中的所有内容都是元素,并且您希望元素的xpath执行此操作,那么 element.getroottree().getpath(element) 会完成任务的。

from lxml import etree

xml = '''
<test>
    <a/>
    <b>
       <i/>
       <ii/>
    </b>
</test>
'''
tree = etree.fromstring(xml)

for element in tree.iter():
    print element.getroottree().getpath(element)