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角度5显示嵌套的问题并回答父项下的显示项

angular5 typescript angular

devmrh · 技术社区 · 7 年前

这是我的服务器对问题和答案的响应。它是一个数组。

[
    {
        "id": 1,
        "product": 1,
        "user": "alex",
        "text": "is it ok?",
        "parent_id": null,
    },
    {
        "id": 2,
        "product": 1,
        "user": "john doe",
        "text": "yes its ok.",
        "publish": true,
        "parent_id": 1,
    },
      {
        "id": 3,
        "product": 1,
        "user": "shiva",
        "text": "how can i .. . .",
        "publish": true,
        "parent_id": null,
    },
]

第二项(id 2)是对问题1的响应,因为它有partent_id=1,id 3是独立的问题

我想在嵌套的顺序列表中显示每个问题下的回答如果这个问题有任何答案…我该怎么做?

我做了一些这样的事情,但它认为它完全错误,谁能指导我做正确的事?谢谢

我的“获取问题和答案”组件

  this._store.viewSingleProductQA(this.product.product_id).subscribe(data => {
      this.questions = data;

     this.responses = this.questions.filter(d => d.parent_id == this.questions.id)
    });

HTML:

  <div>{{question?.user}}</div>
  <div>{{question.text}}</div>
</div>
<div *ngFor="let res of responses">
  {{res.text}}
</div>

2 回复 | 直到 7 年前

Nandita Sharma 7 年前

试试这个html,其中的响应如下

responses = [
    {
        "id": 1,
        "product": 1,
        "user": "alex",
        "text": "is it ok?",
        "parent_id": null,
    },
    {
        "id": 2,
        "product": 1,
        "user": "john doe",
        "text": "yes its ok.",
        "publish": true,
        "parent_id": 1,
    },
      {
        "id": 3,
        "product": 1,
        "user": "shiva",
        "text": "how can i .. . .",
        "publish": true,
        "parent_id": null,
    },
]

<div *ngFor="let res of responses">
  <div *ngIf="res.parent_id === null">
    Ques : {{res.text}}
    <br/>
    Answers :
    <ng-container *ngFor="let res2 of responses">

       <div *ngIf="res2.parent_id === res.id">
         {{res2.text}}
       </div>
    </ng-container>
  </div>

</div>

检查这个 fiddle

Eliseo 7 年前

如果只有一个回应(不是回应的回应),你总是可以做

<div *ngFor="let q of questions>
   <!--only want to show the question, not the answer-->
   <div *ngIf="!q.parent_id> 
      {{q.user}}{{q.text}}
      <div *ngFor="let a of question.filter(t=>t.parent_id==q.id)>
          response:{{a.user}}{{a.text}}
      </div>
   <div>
</div>

或者“映射”数组以创建新的问答列表

this.questionAndAndwers=this.question
          .filter(q=>!q.parent_id)
          .map(q=>{
               let answer=this.question.find(i=>i.parent_id==q.id)
               return {...q,
                       a_user:answer?answer.user:null,
                      a_text:answer?answer.text:null
                      ..others properties....
               }
          })

编辑:完成答案我们也可以像

this.questionAndAndwers=this.question
          .filter(q=>!q.parent_id)
          .map(q=>{
               return {...q,
                       answers:this.question.filter(i=>i.parent_id==q.id)
               }
          });

或者如果有回复的话…我们可以做一个递归函数

getAnswers(questions:any,id:any)
  {
    return questions
           .filter(i=>i.parent_id==id)
           .map(q=>{
             return {...q,
                     answers:this.getAnswers(questions,q.id)}
           })
  }
//And
this.questionAndAndwers=this.getAnswers(this.question,null)

然后我们可以做一个组件

@Component({
  selector: 'app-question',
  template: `<div *ngFor="let q of questions">
              {{q.user}}{{q.text}}
              <app-question [questions]=q.answers></app-question>
           </div>`
})
export class QuestionComponent  {
  @Input() questions: any;
}

//In our app.component
<app-question [questions]="questionAndAndwers"></app-question>