用tuple、list和integer合并2个列表

如果元组中的前两项不会因问题而改变,则可以这样尝试。

list1 =  [(6, 0, [3120])]
list2 = [(6, 0, [3116])]

def add_two_lists(list1, list2):
    # Destructure the first element which is a tuple in both lists
    l1_first, l1_second, rest_first = list1[0]
    l2_first, l2second, rest_second = list2[0]
    res_tuple = (l1_first, l1_second, rest_first + rest_second)
    res_list = [res_tuple]
    return res_list

print(add_two_lists(list1, list2))

这应该能帮到你:

list1 =  [(6, 0, [3120])]

list2 = [(6, 0, [3116])]

temp_list1 = list(list1[0])

temp_list2 = list(list2[0])

temp_list1[2].append(temp_list2[2][0])

final_tuple= tuple(temp_list1)

list3=[]
list3.append(final_tuple)

print(list3)

印刷品:

[(6, 0, [3120, 3116])]

对于示例输入,可以执行以下操作:

list3 = [list1[0][:2] + tuple([list1[0][2] + list2[0][2]])]
# [(6, 0, [3120, 3116])]

list1 = [(6, 0, [3120,2121,14141])]
list2 = [(6, 0, [3116])]

list3 = [list1[0][:2] + tuple([list1[0][2] + list2[0][2]])]

print(list3)
# [(6, 0, [3120, 2121, 14141, 3116])]

假设list1和list 2的长度相等,可以执行以下操作。

list1 =  [(6, 0, [2,4,8]),(3, 5, [3,5,7]),]
list2 =  [(6, 0, [10,12,14]),(3, 5, [9,11,13,15]),]

final_list = []

for i, v in enumerate(list1):
    list3 = [(list1[i])] + [(list2[i])]
    final = list3[0][:2] + tuple([list3[0][2] + list3[1][2]])
    final_list.append(final)

print(final_list)

Out[1]: [(6, 0, [2, 4, 8, 10, 12, 14]), 
         (3, 5, [3, 5, 7, 9, 11, 13, 15])]