Python代码类curl

这是相当于 pycurl :

import pycurl
from StringIO import StringIO

response_buffer = StringIO()
curl = pycurl.Curl()

curl.setopt(curl.URL, "http://api.foursquare.com/v1/venue.json?vid=2393749")

curl.setopt(curl.USERPWD, '%s:%s' % ('youruser', 'yourpassword'))

curl.setopt(curl.WRITEFUNCTION, response_buffer.write)

curl.perform()
curl.close()

response_value = response_buffer.getvalue()

尝试使用邮件头进行身份验证:“

从 Python urllib2 Basic Auth Problem

import urllib2
import base64

req = urllib2.Request('http://api.foursquare.com/v1/venue.json?vid=%s' % self.venue_id)
req.add_header('Authorization: Basic ',base64.b64encode('email:password'))
res = urllib2.urlopen(req)

我更愿意在子流程中运行命令行curl。这避免了python、pycurl和libcurl所有可能的版本匹配问题。观察到pycurl已经两年没有被接触过了,而且只在Python 2.5中被列为支持,这让我很警惕。 --约翰

   import subprocess

   def curl(*args):
        curl_path = '/usr/bin/curl'
        curl_list = [curl_path]
        for arg in args:
            curl_list.append(arg)
        curl_result = subprocess.Popen(
                     curl_list,
                     stderr=subprocess.PIPE,
                     stdout=subprocess.PIPE).communicate()[0]
        return curl_result

    answer = curl('-u', 'email:password', 'http://api.foursquare.com/v1/venue.json?vid=2393749')

将人肉卷导入为投掷

r = hurl.get('http://api.foursquare.com/v1/venue.json?vid=2393749', auth=('email','password'))

r.content中的Json数据

使用pycurl

• http://pycurl.sourceforge.net/

教程中有一个关于SO的讨论

• What good tutorials exist for learning pycURL?

import sys
import pycurl

class ContentCallback:
        def __init__(self):
                self.contents = ''

        def content_callback(self, buf):
                self.contents = self.contents + buf

t = ContentCallback()
curlObj = pycurl.Curl()
curlObj.setopt(curlObj.URL, 'http://www.google.com')
curlObj.setopt(curlObj.WRITEFUNCTION, t.content_callback)
curlObj.perform()
curlObj.close()
print t.contents