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对象的XML反序列化组

serialization c#

samuel · 技术社区 · 16 年前

这是XML文档:

<?xml version="1.0" encoding="utf-8" ?>
 <ToolBars>
   <ToolBarSet id="1" buttonsCounter="4"  width="252">
      <ToolBarItem id="1" Command="Command11" Icon="pic11" Enabled="true" Visible="true" />
      <ToolBarItem id="2" Command="Command12" Icon="pic12" Enabled="true" Visible="true" />
      <ToolBarItem id="3" Command="Command13" Icon="pic13" Enabled="true" Visible="true" />
      <ToolBarItem id="4" Command="Command14" Icon="pic14" Enabled="false" Visible="true" />      
    </ToolBarSet>
    <ToolBarSet  id="2" buttonsCounter="2"  width="170">
      <ToolBarItem id="1" Command="Command21" Icon="pic11" Enabled="true" Visible="true" />
      <ToolBarItem id="2" Command="Command22" Icon="pic22" Enabled="true" Visible="true" /> 
    </ToolBarSet>
  </ToolBars>

我想填充适当的类,这是我的代码:
(公众只是为了测试)

class Program
    {
        static void Main(string[] args)
        {
            ToolBars test;

            XmlSerializer mySerializer = new XmlSerializer(typeof(ToolBars));
            using (FileStream myFileStream = new FileStream("c:\\XMLFile1.xml", FileMode.Open))
            {

                test = (ToolBars)mySerializer.Deserialize(myFileStream);
            }



        }
    }

    [Serializable]
    [System.Xml.Serialization.XmlRoot("ToolBars")]
    public class ToolBars
    {
        public int id;
        public int buttonsCounter;
        public int width;

        [XmlArray("ToolBarSet")]
        [XmlArrayItem("ToolBar", typeof(Toolbar))]
        public List<Toolbar> toolbars = new List<Toolbar>();             

    }

    [Serializable]
    public class Toolbar
    {      
        [XmlArray("ToolbarItem")]
        [XmlArrayItem("ToolbarItem", typeof(ToolbarItem))]
        public List<ToolbarItem> toolbarItems = new List<ToolbarItem>();

    }

    [Serializable]
    public class ToolbarItem
    {
        public string command;

        public int id;

        public string icon;

        public bool visible;

        public bool enabled;

    }

如何使其工作?

3 回复 | 直到 16 年前

João Angelo 16 年前

可以使用此XML格式:

<?xml version="1.0" encoding="utf-8" ?>
<ToolBarConfiguration>
  <ToolBars>
    <ToolBarSet id="1" buttonsCounter="4" width="252">
      <ToolBarItems>
        <ToolBarItem 
          id="1" 
          Command="Command11" Icon="pic11" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="2" 
          Command="Command12" Icon="pic12" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="3" 
          Command="Command13" Icon="pic13" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="4" 
          Command="Command14" Icon="pic14" Enabled="false" Visible="true"/>
      </ToolBarItems>
    </ToolBarSet>
    <ToolBarSet id="2" buttonsCounter="2"  width="170">
      <ToolBarItems>
        <ToolBarItem 
          id="1" 
          Command="Command21" Icon="pic11" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="2" 
          Command="Command22" Icon="pic22" Enabled="true" Visible="true"/>
      </ToolBarItems>
    </ToolBarSet>
  </ToolBars>
</ToolBarConfiguration>

对于这些类:

[Serializable]
[XmlRoot("ToolBarConfiguration")]
public class ToolBars
{
    [XmlArray("ToolBars")]
    [XmlArrayItem("ToolBarSet", typeof(Toolbar))]
    public List<Toolbar> toolbars = new List<Toolbar>();
}

[Serializable]
public class Toolbar
{
    [XmlAttribute("id")]public int id;
    [XmlAttribute("buttonsCounter")]public int buttonsCounter;
    [XmlAttribute("width")]public int width;

    [XmlArray("ToolBarItems")]
    [XmlArrayItem("ToolBarItem", typeof(ToolbarItem))]
    public List<ToolbarItem> toolbarItems = new List<ToolbarItem>();
}

[Serializable]
public class ToolbarItem
{
    [XmlAttribute("Command")]public string command;
    [XmlAttribute("id")]public int id;
    [XmlAttribute("Icon")]public string icon;
    [XmlAttribute("Visible")]public bool visible;
    [XmlAttribute("Enabled")]public bool enabled;
}

编辑: 在你的问题中,你也会说:

(公众只是为了测试)

请注意,对于XML序列化,只序列化对象的公共属性和字段。

marc_s MisterSmith 16 年前

你能做什么总是在这种情况下做的是

获取XML文件并运行它 xsd.exe 在命令行上->这将为您提供一个XSD架构文件
获取新创建的XSD文件并运行它 XSD-EXE 与 /c 参数->这将为您提供一个C文件(如果需要vb.net,还可以使用/L:vb),该文件将能够反序列化XML

只要在xsd.exe的两次运行过程中没有出现任何致命错误,就应该可以很好地执行,并且应该能够在一秒钟内将任何XML反序列化为C对象。

马克

Andre Pena 16 年前

只需将类替换为以下内容:

[XmlRoot("ToobBars")]
public class ToolBars : List<ToolbarSet>
{

}

public class ToolbarSet
{
    [XmlAttribute]
    public int id { get; set; }
    [XmlAttribute]
    public int buttonsCounter { get; set; }
    [XmlAttribute]
    public int width { get; set; }

    public List<ToolbarItem> ToolBarItems = new List<ToolbarItem>();
}

public class ToolbarItem
{
    [XmlAttribute]
    public string command { get; set; }
    [XmlAttribute]
    public int id { get; set; }
    [XmlAttribute]
    public string icon { get; set; }
    [XmlAttribute]
    public bool visible { get; set; }
    [XmlAttribute]
    public bool enabled { get; set; }
}