正确使用SkipTo

我以前使用过pyparsing,但只用于小任务,这次我尝试将其用于更复杂的任务。

我想跳过一个VHDL架构块,它看起来像这样

architecture Behav of Counter is
  ...many statements I'm not interested in at this point...
end architecture;

以下是我尝试的:

import pyparsing as pp
pp_identifier = pp.Regex(r'([a-zA-Z_][\w]*)')('identifier')
def Keyword(matchString):
    'VHDL keywords are caseless and consist only of alphas'
    return pp.Keyword(matchString, identChars=pp.alphas, caseless=True)

pp_architecture = (
    Keyword('architecture')
    + pp_identifier
    + Keyword('of').suppress()
    + pp_identifier
    + Keyword('is').suppress()
    + Keyword('end')
    + Keyword('architecture')
    )

print(pp_architecture.parseString('''
architecture beh of sram is end architecture
''', parseAll=True))

# this works as I expected, it prints
# ['architecture', 'beh', 'sram', 'end', 'architecture']

pp_architecture 使用 SkipTo 它失败了:

pp_architecture = (
    Keyword('architecture')
    + pp_identifier
    + Keyword('of').suppress()
    + pp_identifier
    + Keyword('is').suppress()
    + pp.SkipTo(Keyword('end') + Keyword('architecture'))
    )

print(pp_architecture.parseString('''
architecture beh of sram is end architecture
''', parseAll=True))
Traceback (most recent call last):
  File "<stdin>", line 3, in <module>
  File "C:\Python27\lib\site-packages\pyparsing.py", line 1125, in parseString
    raise exc
pyparsing.ParseException: Expected end of text (at char 29), (line:2, col:29)

我还尝试在两个文本之间添加其他文本 is 和 end (我希望被跳过)确保没有“空跳过”的问题,但这也没有帮助。