在导出之前,使用额外的中间件动态包装命名的导出

您将在哪里确定哪个包装中间件?

你可以做些像

export const funA = middleware => params => 'funA'
export const funB = middleware => params => 'funB'

import { funA } from './module.js'

const funFunA = middleware(funA)

但这听起来越来越像是函数组合的例子:

import { funA } from './module.js'
import { nextFun } from './other.js'

const funFunA = compose(nextFun, funA)

Arrow 单子

https://evilsoft.github.io/crocks/docs/crocks/Arrow.html

编辑:

const _funA = a => b

export const funA = (...args) => {
  switch (currentMood) {
    case 'saucy': return sauce(_funA(...args))
    default: return _funA(...args)
}

wrapper 在每一行中,可以使用分解结构赋值和命名导出。然而,这需要重复 { funA, funB, ..., funXYZ } .

import { mapValues } from 'lodash';

const wrapper = params => fun => {
    // some extra logic
    Object.assign(params, { extra: 'data' });
    return fun(params);
};

let funA = params => 'hello funA';
let funB = params => 'hello funB';

let { funA, funB } = mapValues({ funA, funB }, wrapper);

export { funA, funB };