如何使用Jericho HTML解析器迭代纯文本段

所有不在任何子元素中的纯文本段,对吗?

public static Iterator<Segment> directPlainTextChildren(Element elem) {
    final Iterator<Segment> it = elem.getContent().getNodeIterator();
    final List<Segment> results = new LinkedList<Segment>();
    final List<Element> children = elem.getChildElements();
    while (it.hasNext()) {
        Segment cur = it.next();
        if (!(cur instanceof Tag) && !(cur instanceof CharacterReference)) {
            for (Element child : children)
                if (child.contains(cur)) continue;
            results.add(cur);
        }
    }
    return results.iterator();
}

一个元素应该有几个直接子元素,而element::contains(segment)方法只是一个简单的边界检查,因此性能应该足够。

编辑: 如果您想添加迭代所有直接子段的能力,它将如下所示:

public static Iterator<Segment> getChildSegments(Element elem) {
    final Iterator<Segment> it = elem.getContent().getNodeIterator();
    final List<Segment> results = new LinkedList<Segment>();
    final List<Element> children = elem.getChildElements();
    while (it.hasNext()) {
        Segment cur = it.next();
        if (cur instanceof CharacterReference)
            results.add(cur);
        else if (cur instanceof Tag) {
            if (cur instanceof StartTag)
                results.add(((StartTag)cur).getElement());
        }
        else {
            for (Element child : children)
                if (child.contains(cur)) continue;
            results.add(cur);
        }
    }
    return results.iterator();
}

使用上面gunslinger47中的方法,以下返回元素elem的immediate(第一个子代)子段:

public static List<Segment> getChildSegments(Element elem) {

    final Iterator<Segment> it = elem.getContent().getNodeIterator();
    final List<Segment> results = new LinkedList<Segment>();
    final List<Element> children = elem.getChildElements();

    while (it.hasNext()) {
        Segment cur = it.next();
        if (!(cur instanceof Tag) && !(cur instanceof CharacterReference) && !cur.isWhiteSpace()) {
            boolean enclosed = false;
            for (Element child : children) {
                if (child.encloses(cur)) { 
                    enclosed = true;
                }
            }
            if (!enclosed) results.add(cur);
        } else {
            for (Element child : children) {
                if (child.getStartTag().equals(cur)) {
                    results.add(cur);
                    break;
                }
            }
        }
    }
    return results;
}