Python:如何组合来自2个函数的返回值,并使用线程将其附加到列表中?

import threading
threading_list = []
def func1():
   threading_list.append("HTML")

def func2():
   threading_list.append("IS FUN")

thread1 = threading.Thread(target=func1)
thread2 = threading.Thread(target=func2)

x = thread1
y = thread2

x.start()
y.start()

print(threading_list)

threadlist 您正在保存线程 变量 ,这就是您在输出中看到的是它们作为字符串的表示。

您无法获得在不同线程中运行的函数的返回值。 您可以选择:

1. 使用 multithreading

:

from multiprocessing.pool import ThreadPool
def func1():
  return 'HTML'

def func2():
  return 'IS FUN'


pool = ThreadPool(processes=1)

return_values = []

return_values.append(pool.apply(func1, ())) # Using apply for synchronous call directly returns the function return value.
func2_result = pool.applyasync(func2) # Using applyasync for asynchronous call will require a later call.

return_values.append(func2_result.get())  # get return value from asynchronous call to func2.

print(return_values)

2. 使用可变对象(如列表)保存返回值:

:

return_values = []
def func1():
   return_values.append('HTML')

def func2():
   return_values.append('IS FUN')

# rest of your code here
print(return_values)

您将获得:

['HTML', 'IS FUN']