python在json结构中成为兄弟

可能您可以尝试使用以下方法获取与输入值匹配的目标列表( 如果期望单个值,您可以简单地 [0] 从列表中获取单个项目 )例如 goal_val = 'A1' :

target = [val['target'] for _, val in my_data.items() if val['goal'] == goal_val]

下面是一个简单的单行解决方案:

d = {
  "conservative": {
    "goal": "A1",
    "target" : 60000,
    "oneoff": 6000,
    "regular": 600
  },
  "moderate": {
    "goal": "A2",
    "target": 70000,
    "oneoff": 7000,
    "regular": 710
  },
  "optimistic": {
    "goal": "A3",
    "target": 80000,
    "oneoff": 8000,
    "regular": 800
  }
}

goal = "A1" # <-- Your goal here

target = next(v['target'] for _, v in d.items() if v['goal'] == goal)
# target == 60000

这将使用生成器表达式来避免执行超出需要的任何迭代。 next() 将确保只返回一个值。

这可以很容易地修改以返回完整的匹配字典:

match = next(v for k, v in d.items() if v['goal'] == goal)
# match == {"goal": "A1", target: 60000, ...}

以下代码是我的朋友:

data = {
  "conservative": {
    "goal": "A1",
    "target" : 60000,
    "oneoff": 6000,
    "regular": 600
  },
  "moderate": {
    "goal": "A2",
    "target": 70000,
    "oneoff": 7000,
    "regular": 710
  },
  "optimistic": {
    "goal": "A3",
    "target": 80000,
    "oneoff": 8000,
    "regular": 800
  }
}

goal_required = 'A1'

for obj in data:
    if data[obj]['goal'] == goal_required:
        target = data[obj]['target']
        print("Object {} with the goal {} needs a target of {}".format(obj, goal_required, target))

其输出:

Object conservative with the goal A1 needs a target of 60000