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在SpeechRecognition包中使用语法时出现运行时错误

cmusphinx grammar speech-recognition python

1

user3303504 · 技术社区 · 7 年前

所以我试着用语法 speech_recognition.recognize_sphinx() 但是,我得到以下错误:

RuntimeError: Decoder_set_fsg returned -1

这是我的代码:

主要的py公司

# Dependencies:
import speech_recognition as sr

# Collect audio sample
r = sr.Recognizer()
print('Please say "perquisition":')
with sr.Microphone() as source:
    audio_en = r.listen(source)
print('Processing...')

# Attempt to convert the speech to text
try:
    print(r.recognize_sphinx(audio_en, grammar='perquisition.gram'))
except sr.UnknownValueError:
    print("Sphinx could not understand audio")
except sr.RequestError as e:
    print("Sphinx error; {0}".format(e))

特权。克

#JSGF V1.0;
grammar perquisition;
// Grammar rule names should be [a-zA-Z0-9] only!
public <perquisition> = ( perquisition );

有什么想法吗?

1 回复 | 直到 7 年前

1

user3303504 7 年前

这里有一些事情掩盖了潜在的bug。 speech_recognition.recognize_sphinx() 只是几个CMUsphinx命令的包装器,可以找到 here 第746行。这个问题有点混乱,因此我们将重点关注下面的代码片段:

# Dependencies
import speech_recognition as sr
import os
import pocketsphinx as ps

# Manually point to the grammar file
grammar = 'search.gram'
try:
    # Point to the model files
    language_directory = os.path.join(os.path.dirname(os.path.realpath(__file__)), "pocketsphinx-data", "en-US")
    acoustic_parameters_directory = os.path.join(language_directory, "acoustic-model")
    language_model_file = os.path.join(language_directory, "language-model.lm.bin")
    phoneme_dictionary_file = os.path.join(language_directory, "pronounciation-dictionary.dict")

    # Create a decoder object with our custom parameters
    config = ps.Decoder.default_config()
    config.set_string("-hmm",
                      acoustic_parameters_directory)  # set the path of the hidden Markov model (HMM) parameter files
    config.set_string("-lm", language_model_file)
    config.set_string("-dict", phoneme_dictionary_file)
    config.set_string("-logfn", os.devnull)  # <--- Prevents you from seeing the actual bug!!!
    decoder = ps.Decoder(config)

    # Convert grammar
    grammar_path = os.path.abspath(os.path.dirname(grammar))
    grammar_name = os.path.splitext(os.path.basename(grammar))[0]
    fsg_path = "{0}/{1}.fsg".format(grammar_path, grammar_name)
    if not os.path.exists(fsg_path):  # create FSG grammar if not available
        jsgf = ps.Jsgf(grammar)
        rule = jsgf.get_rule("{0}.{0}".format(grammar_name))
        fsg = jsgf.build_fsg(rule, decoder.get_logmath(), 7.5)
        fsg.writefile(fsg_path)
        print('Successful JSFG to FSG conversion!!!')

    # Pass the fsg file into the decoder
    decoder.set_fsg(grammar_name, fsg)  # <--- BUG IS HERE!!!

except Exception as e:
    print('Ach no! {0}'.format(e))
finally:
    os.remove('search.fsg')  # Remove again to help prove that the grammar to fsg conversion isn't at fault

运行该代码时,我们会发现错误出现了,但日志信息也被关闭了!打开后,大量文本会被丢弃到终端中,这可能会造成麻烦。在这种情况下,将其重新打开以发现。。。

...
ERROR: "fsg_search.c", line 141: The word 'perquisition' is missing in the dictionary
...

现在我们有进展了。这给我们留下了两个选择之一。首先我们可以扫描字典( pocketsphinx.get_model_path()+'/cmudict-en-us.dict' 或类似的)来确定一个单词是否存在。然后我们可以决定是忽略这个词,还是将它添加到字典中。

添加到字典不一定是直接的。。。这取决于它与词典中其他单词的相似程度,你可能会侥幸逃脱。否则,您还必须重新培训模型。关于如何做到这一点,可以找到更好的解释 here 享受