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从数组中删除特定日期

javascript

Tobias Glaus · 技术社区 · 6 年前

我得到一个数组,其中包含指定范围内的日期(格式为日期,而不是字符串):

var dates = function(startDate, endDate) {
  var dates = [],
      currentDate = startDate,
      addDays = function(days) {
        var date = new Date(this.valueOf());
        date.setDate(date.getDate() + days);
        return date;
      };
  while (currentDate <= endDate) {
    dates.push(currentDate);
    currentDate = addDays.call(currentDate, 1);
  }
  return dates;
};

var startDate = new Date("2019-04-01");
var endDate = new Date("2019-04-26");

var dates = dates(startDate, endDate);

然后我像这样过滤掉了周末:

var workingDays = dates.filter(function(e, index){  
  return (e.getDay() != 0 && e.getDay() != 6);
});

到目前为止效果很好,但我的问题是我也需要过滤掉假期。我尝试使用与周末相同的过滤功能,如下所示:

var holidays = [new Date("2019-04-19"), new Date("2019-04-22")];

var workingDays = dates.filter(function(e, index){
  return (e.getDay() != 0 && e.getDay() != 6 && e != holidays);
});

这不起作用,只是返回了与以前相同的数组。

是否有人知道如何实现这一点,并且只筛选出变量中的指定日期?

3 回复 | 直到 6 年前

Roko C. Buljan 6 年前

因为我们不能比较两个日期对象,所以我们可以比较它们毫秒时间戳对应项,如:

!holidays.some(d => +d === +e)

哪里 +d 和 +e 是 new Date().getTime()

例子:

var dates = function(startDate, endDate) {
  var dates = [],
      currentDate = startDate,
      addDays = function(days) {
        var date = new Date(this.valueOf());
        date.setDate(date.getDate() + days);
        return date;
      };
  while (currentDate <= endDate) {
    dates.push(currentDate);
    currentDate = addDays.call(currentDate, 1);
  }
  return dates;
};

var startDate = new Date("2019-04-01");
var endDate = new Date("2019-04-26");
var dates = dates(startDate, endDate);
var holidays = [new Date("2019-04-19"), new Date("2019-04-22")];

var workingDays = dates.filter(function(e, index){
  return (e.getDay() != 0 && e.getDay() != 6 && !holidays.some(d => +d === +e));
});

console.log(workingDays)

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/some

Jelle 6 年前

var holidays = [new Date("2019-04-19").toString(), new Date("2019-04-22").toString()];
var dates = [new Date("2019-04-19"), new Date("2019-04-22"), new Date("2019-01-21")];

var workingDays = dates.filter(function(e, index){
  return (e.getDay() != 0 && e.getDay() != 6 && holidays.indexOf(e.toString()) === -1);
});

console.log(workingDays)

因为日期是对象,所以我们需要一些独特的属性来检查它们。在这种情况下,您可以尝试以下操作。但我相信有一些更优化和优雅的解决方案

Kamil KieÅczewski 6 年前

变化 e != holidays 到 !holidays.some( x => +x=== +e )

说明: +x 是呼叫的快捷方式 x.getTime() 用于比较日期时间戳。

var dates = function(startDate, endDate) {
  var dates = [],
      currentDate = startDate,
      addDays = function(days) {
        var date = new Date(this.valueOf());
        date.setDate(date.getDate() + days);
        return date;
      };
  while (currentDate <= endDate) {
    dates.push(currentDate);
    currentDate = addDays.call(currentDate, 1);
  }
  return dates;
};

var startDate = new Date("2019-04-01");
var endDate = new Date("2019-04-26");

var dates = dates(startDate, endDate);


var holidays = [new Date("2019-04-19"), new Date("2019-04-22")];

var workingDays = dates.filter(function(e, index){
  return (e.getDay() != 0 && e.getDay() != 6 && !holidays.some(x=>+x===+e));
});

console.log(workingDays);