带有空白的列表的文本表示

这个 intspan 图书馆这样做

>>> mylist =  [2, 5,6,7, 11,12, 19,20,21,22, 37,38, 40]
>>> from intspan import intspan
>>> str(intspan(mylist))
'2,5-7,11-12,19-22,37-38,40'

你可以试试这个:

mylist = [2, 5, 6, 7, 11, 12, 19, 20, 21, 22, 37, 38, 40]
ans = []
ret = ''

# assuming mylist is sorted
for i in mylist:
    if len(ans) == 0 or ans[-1][1] < i - 1: #if the array is empty or we can't add current value to the last range
        ans.append([i, i]) # make a new range
    else:
        ans[-1][1] = i # add to last range

for i in ans:
    # formating
    if i != ans[0]: 
        ret = ret + ' '
    if i[0] == i[1]: 
        ret = f'{ret}{i[0]},'
    else:
        ret = f'{ret}{i[0]}-{i[1]},'
print(ret)

希望这能有所帮助!

def collapseRuns(L):
    if not L: return ''

    answer = [[L[0]]]
    for num in L[1:]:
        if num == answer[-1][-1]+1:
            answer[-1].append(num)
        else:
            answer.append([num])

    for i,L in enumerate(answer):
        if len(L) > 1:
            answer[i] = f"{L[0]}-{L[-1]}"
        else:
            answer[i] = f"{L[0]}"

    return ', '.join(answer)

测试:

In [158]: collapseRuns(L)
Out[158]: '2, 5-7, 11-12, 19-22, 37-38, 40'

使用下面的代码片段:

mylist =  [2, 5,6,7, 11,12, 19,20,21,22, 37,38, 40]
newlist = []
i = 0
while(i < len(mylist)):
    j = i
    if(i+1 < len(mylist)-1):
        while(mylist[i]+1 == mylist[i+1]):
            i = i+1
    newlist.append(mylist[j]) if j == i else newlist.append(str(mylist[j]) + " - " + str(mylist[i]))
    i = i+1

:)