谁的责任是解放斯库夫

netlink_kernel_create() 函数指针作为参数传递给此函数,当在该套接字上接收到消息时调用该函数。此回调函数接收 sk_buff

我的问题是谁的责任是解放这个 ?

示例代码

#包括<linux/module.h>

#包括<linux/netlink.h>

结构sock*nl\u sk=NULL;

静态void my\u nl\u recv\u msg(struct sk\u buff*skb){

struct nlmsghdr *nlh;  
int pid;  

printk(KERN_INFO "Entering: %s\n", __FUNCTION__);  

nlh=(struct nlmsghdr*)skb->data;  
printk(KERN_INFO "Netlink received msg payload: %s\n",  
    (char*)NLMSG_DATA(nlh));  
pid = nlh->nlmsg_pid; /*pid of sending process */  
NETLINK_CB(skb).dst_group = 0; /* not in mcast group */  
NETLINK_CB(skb).pid = 0;      /* from kernel */  
//printk("About to send msg bak:\n");  
//netlink_unicast(nl_sk,skb,pid,MSG_DONTWAIT);

静态int\uu init hello\u init(void){

printk("Entering: %s\n",__FUNCTION__);  
nl_sk=netlink_kernel_create(&init_net, NETLINK_USER, 0,  
        my_nl_recv_msg, NULL, THIS_MODULE);  
if(!nl_sk)  
{  
    printk(KERN_ALERT "Error creating socket.\n");  
    return -10;  
}  
return 0;