mixin中的super()`

当我创建一个mixin类来扩展 __init__

class ExtraValuemixin:

    def __init__(self, *args, **kwargs)  -> None:
        super().__init__(*args, **kwargs)
        # some extra initialization
        self._extra_value = 1

    def retrieve_extra_value(self):
        return self._extra_value

Too many arguments for "__init__" of "object"

*args 或 **kwargs 在 object 的构造函数签名;但这是一个mixin,它依赖于其子代的构造函数。我怎么才能让我明白?

完整示例:

class ExtraValuemixin:

    def __init__(self, *args, **kwargs)  -> None:
        super().__init__(*args, **kwargs)
        # some extra initialization
        self._extra_value = 1

    def retrieve_extra_value(self):
        return self._extra_value


class ParentObj:

    def __init__(self, value):
        self.value = value


class ChildObj(ExtraValuemixin, ParentObj):
    pass


obj = ChildObj(value=5)

print(obj.retrieve_extra_value())