如何在pyqt中为QAction重新实现triggered()信号?

我使用Python和PyQt作为接口,使用Yapsi作为添加插件。Yapsy找到了我所有的插件,并将所有插件添加到我的主窗口中的菜单中。每个插件都通过触发信号激活。这个QAction的信号没有参数,我需要知道是什么插件发出了信号。

这是相关代码:

pluginMenu = self.menuBar().addMenu("P&lugins")

# Create plugin manager
self.manager = PluginManager(categories_filter={ "Formatters": Formatter})
self.manager.setPluginPlaces(["plugins"])

# Load plugins
self.manager.locatePlugins()
self.manager.loadPlugins()

# A do-nothing formatter by default
self.formatters = {}

for plugin in self.manager.getPluginsOfCategory("Formatters"):

# plugin.plugin_object is an instance of the plugin
print(plugin.plugin_object.name)
# The method to create action associated each input to default triggered() signal
newAction = self.createAction(plugin.plugin_object.name, slot=self.updatePreview())


self.addActions(pluginMenu, (newAction, None))
self.formatters[plugin.plugin_object.name] = (plugin.plugin_object, newAction)

def updatePreview(self):
    # Here I need know what plugin emit the signal    
    #===================================================================

我想用一些参数将信号与其他信号联系起来,但我不知道怎么做。