使用
rex
可以使这类任务稍微简单一些。
x <- "MSGSRRKATPASRTRVGNYEMGRTLGEGSFAKVKYAKNTVTGDQAAIKILDREKVFRHKMVEQLKREISTMKLIKHPNVVEIIEVMASKTKIYIVLELVNGGELFDKIAQQGRLKEDEARRYFQQLINAVDYCHSRGVYHRDLKPENLILDANGVLKVSDFGLSAFSRQVREDGLLHTACGTPNYVAPEVLSDKGYDGAAADVWSCGVILFVLMAGYLPFDEPNLMTLYKRICKAEFSCPPWFSQGAKRVIKRILEPNPITRISIAELLEDEWFKKGYKPPSFDQDDEDITIDDVDAAFSNSKECLVTEKKEKPVSMNAFELISSSSEFSLENLFEKQAQLVKKETRFTSQRSASEIMSKMEETAKPLGFNVRKDNYKIKMKGDKSGRKGQLSVATEVFEVAPSLHVVELRKTGGDTLEFHKVCDSFYKNFSSGLKDVVWNTDAAAEEQKQ"
library(rex)
re_matches(x,
rex(
capture(name = "amino_acids",
n(any, 6),
"K",
n(any, 6)
)
),
global = TRUE)[[1]]
#> amino_acids
#>1 MSGSRRKATPASR
#>2 GEGSFAKVKYAKN
#>3 GDQAAIKILDREK
#>4 KMVEQLKREISTM
#>5 IEVMASKTKIYIV
#>6 GGELFDKIAQQGR
#>7 VYHRDLKPENLIL
#>8 DANGVLKVSDFGL
#>9 PEVLSDKGYDGAA
#>10 NLMTLYKRICKAE
#>11 WFSQGAKRVIKRI
#>12 LEDEWFKKGYKPP
#>13 AAFSNSKECLVTE
#>14 LENLFEKQAQLVK
#>15 ASEIMSKMEETAK
#>16 LGFNVRKDNYKIK
#>17 GDKSGRKGQLSVA
#>18 HVVELRKTGGDTL
#>19 VCDSFYKNFSSGL
然而,上述是贪婪的,每个K只会出现在一个结果中。
如果要为每个K输出AA
library(rex)
locs <- re_matches(x,
rex(
"K" %if_prev_is% n(any, 6) %if_next_is% n(any, 6)
),
global = TRUE, locations = TRUE)[[1]]
substring(x, locs$start - 6, locs$end + 6)
#> [1] "MSGSRRKATPASR" "GEGSFAKVKYAKN" "GSFAKVKYAKNTV" "AKVKYAKNTVTGD"
#> [5] "GDQAAIKILDREK" "KILDREKVFRHKM" "EKVFRHKMVEQLK" "KMVEQLKREISTM"
#> [9] "REISTMKLIKHPN" "STMKLIKHPNVVE" "IEVMASKTKIYIV" "VMASKTKIYIVLE"
#>[13] "GGELFDKIAQQGR" "AQQGRLKEDEARR" "VYHRDLKPENLIL" "DANGVLKVSDFGL"
#>[17] "PEVLSDKGYDGAA" "NLMTLYKRICKAE" "LYKRICKAEFSCP" "WFSQGAKRVIKRI"
#>[21] "GAKRVIKRILEPN" "LEDEWFKKGYKPP" "EDEWFKKGYKPPS" "WFKKGYKPPSFDQ"
#>[25] "AAFSNSKECLVTE" "ECLVTEKKEKPVS" "CLVTEKKEKPVSM" "VTEKKEKPVSMNA"
#>[29] "LENLFEKQAQLVK" "KQAQLVKKETRFT" "QAQLVKKETRFTS" "ASEIMSKMEETAK"
#>[33] "KMEETAKPLGFNV" "LGFNVRKDNYKIK" "VRKDNYKIKMKGD" "KDNYKIKMKGDKS"
#>[37] "NYKIKMKGDKSGR" "IKMKGDKSGRKGQ" "GDKSGRKGQLSVA" "HVVELRKTGGDTL"
#>[41] "DTLEFHKVCDSFY" "VCDSFYKNFSSGL" "NFSSGLKDVVWNT"