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jQuery:从具有多个节点的HTML字符串中提取最顶层的SVG元素

svg html jquery javascript

Crashalot · 技术社区 · 6 年前

This question 和 this question

目标是从HTML字符串中提取最顶层的SVG元素。

$(htmlString).find("svg") 不起作用。

$($.parseHTML(htmlString)) htmlString 在一个jQuery对象中,可以执行查找并检索最顶层的SVG元素。

HTML字符串示例:

<?xml version="1.0" encoding="iso-8859-1"?>
<!-- Generator: Adobe Illustrator 18.1.1, SVG Export Plug-In . SVG Version: 6.00 Build 0)  -->
<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.1" id="Capa_1" x="0px" y="0px" viewBox="0 0 424 424" style="enable-background:new 0 0 424 424;" xml:space="preserve" width="512px" height="512px">
<g>
    <g>
        <path d="M35,89C15,89,0,74,0,54s15-36,35-36h353c20,0,36,16,36,36s-16,35-36,35H35z" fill="#7c7a7d"/>
        <path d="M388,176c20,0,36,16,36,36s-16,35-36,35H35c-20,0-35-15-35-35s15-36,35-36H388z" fill="#7c7a7d"/>
        <path d="M388,335c20,0,36,15,36,35s-16,36-36,36H35c-20,0-35-16-35-36s15-35,35-35H388z" fill="#7c7a7d"/>
    </g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
<g>
</g>
</svg>

$($.parseHTML(htmlString))的结果,其中htmlString是上面的字符串:

$($.parseHTML(htmlString))

w.fn.init(6) [comment, text, comment, text, svg#Capa_1, text]
0: comment
1: text
2: comment
3: text
4: svg#Capa_1
5: text
length: 6

0 回复 | 直到 6 年前

Kaiido NickSlash 6 年前

你不能使用 find 因为您给jQuery的标记并不表示树:Doctype和comments节点是您的同级节点 <svg> .

filter 为了只保留svg节点,jQuery条目如下:

const $svg = $(`<?xml version="1.0" encoding="utf-8"?>
<!-- comment1  -->
<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.1" id="Capa_1" x="0px" y="0px" viewBox="0 0 424 424">
  <g>
    <g>
      <path d="M35,89C15,89,0,74,0,54s15-36,35-36h353c20,0,36,16,36,36s-16,35-36,35H35z" fill="#7c7a7d"/>
      <path d="M388,176c20,0,36,16,36,36s-16,35-36,35H35c-20,0-35-15-35-35s15-36,35-36H388z" fill="#7c7a7d"/>
      <path d="M388,335c20,0,36,15,36,35s-16,36-36,36H35c-20,0-35-16-35-36s15-35,35-35H388z" fill="#7c7a7d"/>
    </g>
  </g>
</svg>`)
.filter((i, el) => $(el).is('svg'));

console.log($svg.attr('id'));
$svg.find('path').attr('fill', 'red');
$('body').append($svg);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

documentElement 将是你的 <svg> 然后,您将能够从jQuery处理它:

const str = `<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.1" id="Capa_1" x="0px" y="0px" viewBox="0 0 424 424">
  <g>
    <g>
      <path d="M35,89C15,89,0,74,0,54s15-36,35-36h353c20,0,36,16,36,36s-16,35-36,35H35z" fill="#7c7a7d"/>
      <path d="M388,176c20,0,36,16,36,36s-16,35-36,35H35c-20,0-35-15-35-35s15-36,35-36H388z" fill="#7c7a7d"/>
      <path d="M388,335c20,0,36,15,36,35s-16,36-36,36H35c-20,0-35-16-35-36s15-35,35-35H388z" fill="#7c7a7d"/>
    </g>
  </g>
</svg>`;

const doc = (new DOMParser).parseFromString(str, 'image/svg+xml');
// use the second argument (context) of jQuery()
const $svg = $('svg', doc);
console.log($svg.attr('id'));
$svg.find('path').attr('fill', 'red');
$('body').append($svg);

<脚本src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js“></脚本>