Appengine Django模板-读取模板标记

听起来像是你的脚中弹了。让我们假装不该责怪我们并解决它:

entry = """{%block price%}$259{%endblock%}  
{%block buy%}http://www.highbeam.co.nz/store/index.php?route=product/product&path=6&product_id=116{%endblock%}  
{%block info%}http://www.inov-8.co.nz/oroc280.html{%endblock%}   """

parsedentry = dict([(j[0].split(' ')[-1], j[-1]) for j in [i.partition("%}") for i in entry.split("{%endblock%}")] if j[0].split(' ')[-1]])

print parsedentry['price']

更新1 固定为遍历整个节点树。

更新2 实际上已经测试过了,现在可以用了。

这里有一种方法。

from django.template import Template, Context

t = Template(template_string) # get it with open(filename).read() I guess


def get_block_contents(t, block_name, context=None):
    if context is None:
        context = Context()
    stack = t.nodelist[:]
    while stack:
        node = stack.pop()
        if hasattr(node, 'name') and node.name == block_name:
            return node.render(context)
        if hasattr(node, 'nodelist'):
            stack.extend(node.nodelist)
    return False # Or raise an error