将多维数组转换为字符串

林克是你的朋友。

多维数组实现 IEnumerable IEnumerable<T> . 所以首先我们需要一个 能够充分利用LINQ。幸运的是,在本例中,我们知道多维数组中的每个项都是 char

接下来,创建 string char[] . 得到一个 字符[] IEnumerable<char> ToArray() 走开。

using System.Linq;

var build = new string(cube.OfType<char>().ToArray());

这比你想象的要容易:

public static String FlattenToString(this char[,,] array)
{
    var builder = new StringBuilder();

    foreach(var @char in array)
    {
        builder.Append(@char);
    }

    return builder.ToString();
}

var cube = new char[2,2,2];

cube[0,0,0] = 'a';
cube[0,0,1] = 'b';
cube[0,1,0] = 'c';
cube[0,1,1] = 'd';
cube[1,0,0] = 'e';
cube[1,0,1] = 'f';
cube[1,1,0] = 'g';
cube[1,1,1] = 'h';

Console.WriteLine(cube.FlattenToString());

abcdefgh .

string build = string.Concat(cube.Cast<char>());

char[] :

//var cube = new[, ,] { { { 'a', 'b' }, { 'c', 'd' } }, { { 'e', 'f' }, { 'g', 'h' } } };
char[] temp = new char[cube.Length];
Buffer.BlockCopy(cube, 0, temp, 0, temp.Length * sizeof(char));
string build = new string(temp);

char[,,] cube = new char[10, 10, 10];
                for (int z = 0; z < 10; z++)
                {
                    for (int y = 0; y < 10; y++)
                    {
                        for (int x = 0; x < 10; x++)
                        {
                            cube[z, y, x] = (char)(65+x);
                        }
                    }
                }
/* Just Filling data in array*/    
                var s1 = cube.OfType<char>().ToList();
                string s = string.Join("",s1);