扫描ip地址的端口并使用python打印响应状态

我正在尝试访问IP地址的端口并打印 status code (即 200 OK , 502 Bad Gateway 等等)。假设,假设 port 80 在ip地址打开 xx.xx.xx.xxx . 所以 xx.xx.xx.xxx:80 应该给我们 200 OK . 在我的代码中,我使用的是端口 811450 ,它肯定没有打开,也没有运行任何应用程序。但它没有显示任何错误。

import httplib  
import urllib
import socket


class mysocket:


    def __init__(self, sock=None):
        if sock is None:
            self.sock = socket.socket(
                socket.AF_INET, socket.SOCK_STREAM)
        else:
            self.sock = sock

    host = "xx.xx.xx.xxx"
    port = "811450"

    def connect(self, host, port):
        self.sock.connect((host, port))

    def mysend(self, msg):
        totalsent = 0
        while totalsent < MSGLEN:
            sent = self.sock.send(msg[totalsent:])
            if sent == 0:
                raise RuntimeError("socket connection broken")
            totalsent = totalsent + sent

    def myreceive(self):
        chunks = []
        bytes_recd = 0
        while bytes_recd < MSGLEN:
            chunk = self.sock.recv(min(MSGLEN - bytes_recd, 2048))
            if chunk == '':
                raise RuntimeError("socket connection broken")
            chunks.append(chunk)
            bytes_recd = bytes_recd + len(chunk)
        return ''.join(chunks)

建议的实现方法是什么。