从字符串中选择随机文本。xml[重复]

public static int getResId(String resName, Class<?> c) {
    try {
        Field idField = c.getDeclaredField(resName);
        return idField.getInt(idField);
    } catch (Exception e) {
        e.printStackTrace();
        return -1;
    } 
}

就您而言:

getResId(text, String.class);

更好的选择是在xml中创建字符串数组:

<?xml version="1.0" encoding="utf-8"?>
<resources>
    <string-array name="planets_array">
        <item>Mercury</item>
        <item>Venus</item>
        <item>Earth</item>
        <item>Mars</item>
    </string-array>
</resources>

String[] planets = res.getStringArray(R.array.planets_array);
int randomNum = rand.nextInt(planets.size() - 1);
txt.setText(planets[randomNum]);

Resources.class : getIdentifier(resIdName, resTypeName, packageName)

由于资源属于上下文,您需要:

String text = "text_";
 int randomNum = rand.nextInt((100 + 1) + 1; 
text = text + String.valueOf(randomNum);
int textId = getResources().getIdentifier(text, "string", getPackageName());
txt.setText(getString(textId));

It was answered here